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ABA12C - Buying Apples! |
Harish went to a supermarket to buy exactly ‘k’ kilograms apples for his ‘n’ friends. The supermarket was really weird. The pricing of items was very different. He went to the Apples section and enquired about the prices. The salesman gave him a card in which he found that the prices of apples were not per kg. The apples were packed into covers, each containing ‘x’ kg of apples, x > 0 and ‘x’ is an integer. An ‘x’ kg packet would be valued at ‘y’ rupees. So, the placard contained a table with an entry ‘y’ denoting the price of an ‘x’ kg packet. If ‘y’ is -1 it means that the corresponding packet is not available. Now as apples are available only in packets, he decides to buy at most ‘n’ packets for his ‘n’ friends i.e he will not buy more than n packets of apples.
Harish likes his friends a lot and so he does not want to disappoint his friends. So now, he will tell you how many friends he has and you have to tell him the minimum amount of money he has to spend for his friends.
Input
The first line of input will contain the number of test cases, C.
Each test case will contain two lines.
The first line containing N and K, the number of friends he has and the amount of Apples in kilograms which he should buy.
The second line contains K space separated integers in which the ith integer specifies the price of a ‘i’kg apple packet. A value of -1 denotes that the corresponding packet is unavailable.
- 0 < N <= 100
- 0 < K <= 100
- 0 < price <= 1000
Output
The output for each test case should be a single line containing the minimum amount of money he has to spend for his friends. Print -1 if it is not possible for him to satisfy his friends.
Sample I/O
Input: 2 3 5 -1 -1 4 5 -1 5 5 1 2 3 4 5 Output: -1 5
Explanation of test cases:
- As there are only 3 and 4kg packets in the shop, he will not be able to satisfy his friends as he would not be able to buy exactly 5kg of apples.
- He can buy five 1kg packet as he has to buy 5 kg. So the min money he should spend is 5.
Added by: | Kashyap Krishnakumar |
Date: | 2012-01-13 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | Own problem |
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2015-12-27 16:29:57 Shubham Gupta
'n' is not taken into account while determining o/p. I/p: 1 3 4 1 3 -1 -1 Ac. O/p: 4 [he can take 4 packets of one kg,which is more than n] Whereas, actual o/p should have been 5 [One packet of 2kg and two packets of 1kg each,which is equal to n]. Last edit: 2015-12-27 16:31:04 |
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2015-12-25 20:34:33 sneh sajal
note :- one item can be taken multiple times! good DP :) |
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2015-12-14 10:10:12 priyank
nice question |
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2015-12-05 18:39:53 vijay meena
same as Rod cutting. just change max into min thats it |
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2015-10-29 18:57:43 munjal
Not at all good description of the question is provided ........ !!!!!!!!!!!!!!!!!!!!!!!! |
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2015-10-26 19:57:21 LeppyR64
Regardless of everyone's complaining that the test cases do not exploit the fact that n is not considered, a solution that does consider that the number of pacakages is at most n will still get AC (Including mine). Please do mind the constraint that price can be equal to zero. O(k * n * k) |
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2015-09-10 23:27:04 Eknoor Jassal
The statement is not right. There is no use made of the constraint "he will not buy more than n packets of apples." for e.g. n =1 k = 5 and prices = 1 2 3 4 -1. The ans should be -1. But I got an AC with the solution which does not take n into account and gives output as 5 for this test case. The other solution which actually gives -1 got a WA. |
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2015-08-14 20:04:05 Akash
no use of n |
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2015-07-12 13:45:10 poojan
good dp ! just like famous cutting rode problem ! this is my second dp! felling great after solving this one! |
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2015-06-25 09:15:10 janina
easy one......green in 1go.....problem statement is not correct i think......no use of n. |