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ACODE - Alphacode |
Alice and Bob need to send secret messages to each other and are discussing ways to encode their messages:
Alice: “Let’s just use a very simple code: We’ll assign ‘A’ the code word 1, ‘B’ will be 2, and so on down to ‘Z’ being assigned 26.”
Bob: “That’s a stupid code, Alice. Suppose I send you the word ‘BEAN’ encoded as 25114. You could decode that in many different ways!”
Alice: “Sure you could, but what words would you get? Other than ‘BEAN’, you’d get ‘BEAAD’, ‘YAAD’, ‘YAN’, ‘YKD’ and ‘BEKD’. I think you would be able to figure out the correct decoding. And why would you send me the word ‘BEAN’ anyway?”
Bob: “OK, maybe that’s a bad example, but I bet you that if you got a string of length 5000 there would be tons of different decodings and with that many you would find at least two different ones that would make sense.”
Alice: “How many different decodings?”
Bob: “Jillions!”
For some reason, Alice is still unconvinced by Bob’s argument, so she requires a program that will determine how many decodings there can be for a given string using her code.
Input
Input will consist of multiple input sets. Each set will consist of a single line of at most 5000 digits representing a valid encryption (for example, no line will begin with a 0). There will be no spaces between the digits. An input line of ‘0’ will terminate the input and should not be processed.
Output
For each input set, output the number of possible decodings for the input string. All answers will be within the range of a 64 bit signed integer.
Example
Input: 25114 1111111111 3333333333 0 Output: 6 89 1
Added by: | Adrian Kuegel |
Date: | 2005-07-09 |
Time limit: | 0.5s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All |
Resource: | ACM East Central North America Regional Programming Contest 2004 |
hide comments
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2015-12-18 18:37:56
linear memorization and zero is damn tricky!! |
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2015-12-17 15:37:58 Utkarsh
my accepted solution gives 1 as the answer for 100 or 1000..idk why the correct ans should be 0 for both the testcases |
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2015-12-17 14:02:34 Junaid
Finally after working on this problem for more than a day......AC in one go...:)...Thanks for the testcases...... |
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2015-12-09 23:59:44 rahul
if using python and top down approach import sys sys.setrecursionlimit(10000) |
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2015-12-07 08:56:15
Any reason as to why same JAVA code would take 314M one time and 1341M the next in SPOJ? |
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2015-11-28 10:17:49
No need for an array. This problem can be solved even without memoization (full on memoization). |
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2015-11-15 06:19:12 Priyank
Just remember few imp. cases like 10, 20. |
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2015-10-27 13:41:06
If you believe that your code is correct but is not passing some test cases, then look for ALL of the test cases mentioned in the comment section (till the last!!). Last edit: 2015-10-27 13:41:21 |
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2015-10-18 16:00:44 Heartbreak_Kid
what will be the answer for "1101"? |
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2015-10-11 00:35:50 Alex Anderson
Try http://www.spoj.com/problems/PONY2/ for a more advanced version of this problem. |