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ACODE - Alphacode |
Alice and Bob need to send secret messages to each other and are discussing ways to encode their messages:
Alice: “Let’s just use a very simple code: We’ll assign ‘A’ the code word 1, ‘B’ will be 2, and so on down to ‘Z’ being assigned 26.”
Bob: “That’s a stupid code, Alice. Suppose I send you the word ‘BEAN’ encoded as 25114. You could decode that in many different ways!”
Alice: “Sure you could, but what words would you get? Other than ‘BEAN’, you’d get ‘BEAAD’, ‘YAAD’, ‘YAN’, ‘YKD’ and ‘BEKD’. I think you would be able to figure out the correct decoding. And why would you send me the word ‘BEAN’ anyway?”
Bob: “OK, maybe that’s a bad example, but I bet you that if you got a string of length 5000 there would be tons of different decodings and with that many you would find at least two different ones that would make sense.”
Alice: “How many different decodings?”
Bob: “Jillions!”
For some reason, Alice is still unconvinced by Bob’s argument, so she requires a program that will determine how many decodings there can be for a given string using her code.
Input
Input will consist of multiple input sets. Each set will consist of a single line of at most 5000 digits representing a valid encryption (for example, no line will begin with a 0). There will be no spaces between the digits. An input line of ‘0’ will terminate the input and should not be processed.
Output
For each input set, output the number of possible decodings for the input string. All answers will be within the range of a 64 bit signed integer.
Example
Input: 25114 1111111111 3333333333 0 Output: 6 89 1
Added by: | Adrian Kuegel |
Date: | 2005-07-09 |
Time limit: | 0.5s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All |
Resource: | ACM East Central North America Regional Programming Contest 2004 |
hide comments
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2014-09-07 14:54:27 mayank
Did, memoization first, then reduced it to 3 variables. My first DP :) |
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2014-09-01 15:38:47 Dhruv Mullick
Managing 0 is the tricky part. |
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2014-08-28 20:26:15 Anubhav Balodhi
just did it ^_^ |
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2014-08-26 10:07:21 Vaibhav Gosain
my first memoization!!! |
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2014-08-03 08:41:23 kaviraj
AC on the first go.. :-D. My second DP |
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2014-07-22 09:16:54 The Exorcist
take care of following cases: 20 1190 11101 01 30 o/p: 1 0 2 0 0 |
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2014-07-14 08:20:54 Rajat (1307086)
finally done.was a bit hard to guess it was of DP. Take special care of test cases that have 0 in middle. |
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2014-07-06 19:51:47 Vaibhav Goyal
Instead of 5000, take the length of array 100000 otherwise you will get runtime error |
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2014-07-02 15:05:26 jkelava6
@dexter morgan 5010 is eanugh; idk why does it have to be, but take it as one (or few more) spaces for '\0', which meens end of array. @hackr32 "30" is not a "a valid encryption" |
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2014-07-01 16:52:19 classified_01
leaving one tricky condition for 0 might leave with 4 wrong answers ! |