ACODE - Alphacode

Alice and Bob need to send secret messages to each other and are discussing ways to encode their messages:

Alice: “Let’s just use a very simple code: We’ll assign ‘A’ the code word 1, ‘B’ will be 2, and so on down to ‘Z’ being assigned 26.”

Bob: “That’s a stupid code, Alice. Suppose I send you the word ‘BEAN’ encoded as 25114. You could decode that in many different ways!”

Alice: “Sure you could, but what words would you get? Other than ‘BEAN’, you’d get ‘BEAAD’, ‘YAAD’, ‘YAN’, ‘YKD’ and ‘BEKD’. I think you would be able to figure out the correct decoding. And why would you send me the word ‘BEAN’ anyway?”

Bob: “OK, maybe that’s a bad example, but I bet you that if you got a string of length 5000 there would be tons of different decodings and with that many you would find at least two different ones that would make sense.”

Alice: “How many different decodings?”

Bob: “Jillions!”

For some reason, Alice is still unconvinced by Bob’s argument, so she requires a program that will determine how many decodings there can be for a given string using her code.

Input

Input will consist of multiple input sets. Each set will consist of a single line of at most 5000 digits representing a valid encryption (for example, no line will begin with a 0). There will be no spaces between the digits. An input line of ‘0’ will terminate the input and should not be processed.

Output

For each input set, output the number of possible decodings for the input string. All answers will be within the range of a 64 bit signed integer.

Example

Input:
25114
1111111111
3333333333
0

Output:
6
89
1

Added by:Adrian Kuegel
Date:2005-07-09
Time limit:0.5s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All
Resource:ACM East Central North America Regional Programming Contest 2004

hide comments
2020-07-12 17:42:35
Solved in 2nd Attempt.
2020-07-03 07:48:36
try
113011
1010
10110
226210
310

Last edit: 2020-07-03 08:46:10
2020-05-19 04:49:53
This was not a good question, the boundary cases I got to know from the comments. So please check the comments. Also see my submission for more clarity : <snip>

Last edit: 2023-06-07 12:15:04
2020-05-18 19:03:47
I think It should be mentioned that a substring 02 will not be counted valid
2020-05-10 09:05:36
what should be the output for 20201
will 2|020|1 count as a valid partition
2020-05-05 10:11:55
the problem is easy except corner cases like 109, 10009, 20110 etc.
2020-04-29 17:57:40
getting WA .. try Test Cases in the comments
2020-04-29 12:05:03
In 108, will 08 be treated as H or only 10 will be treated?
2020-04-28 17:40:23
Turned such a pretty question into something so ugly thanks to 10 and 20...
2020-04-18 16:05:18
I think this problem is not so much about main logic but about handling corner cases
© Spoj.com. All Rights Reserved. Spoj uses Sphere Engine™ © by Sphere Research Labs.