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ACPC10A - What’s Next |
According to Wikipedia, an arithmetic progression (AP) is a sequence of numbers such that the difference of any two successive members of the sequence is a constant. For instance, the sequence 3, 5, 7, 9, 11, 13 ... is an arithmetic progression with common difference 2. For this problem, we will limit ourselves to arithmetic progression whose common difference is a non-zero integer.
On the other hand, a geometric progression (GP) is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed non-zero number called the common ratio. For example, the sequence 2, 6, 18, 54 ... is a geometric progression with common ratio 3. For this problem, we will limit ourselves to geometric progression whose common ratio is a non-zero integer.
Given three successive members of a sequence, you need to determine the type of the progression and the next successive member.
Input
Your program will be tested on one or more test cases. Each case is specified on a single line with three integers (−10, 000 < a1, a2, a3 < 10, 000) where a1, a2, and a3 are distinct.
The last case is followed by a line with three zeros.
Output
For each test case, you program must print a single line of the form:
XX v
where XX is either AP or GP depending if the given progression is an Arithmetic or Geometric Progression. v is the next member of the given sequence. All input cases are guaranteed to be either an arithmetic or geometric progressions.
Example
Input:
4 7 10
2 6 18
0 0 0
Output:
AP 13
GP 54
Added by: | Omar ElAzazy |
Date: | 2010-11-30 |
Time limit: | 1.799s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | ACPC 2010 |
hide comments
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2012-09-27 02:07:32 hua
If anyone needs some help with this problem, I wrote a quick explanation at <gone> Last edit: 2022-08-10 15:41:49 |
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2012-09-08 06:30:03 shibani
s t necessary that a1<a2<a3?? Last edit: 2012-09-08 06:30:27 |
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2012-09-01 11:17:29 A.Rajkumar
idone all perfectly but still i getting wrong answer which is perfectly working in linux |
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2012-07-31 14:52:27 abc
output for 9 3 1 ? 0 or 0.33333 ? |
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2012-07-23 12:56:13 Shaik Shoeb
one of the easiest problems in spoj that i have come across. :) |
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2012-07-07 09:53:23 bhim
use test condition 2*b==a*c...rather b==(a*c)/2 for test of AP |
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2012-06-30 04:45:31 StupidGuy
I am embarrassed that I submitted this. |
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2012-06-18 14:57:13 akhil_sharma
nice and easy problem....got AC in first attempt |
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2012-06-17 14:05:06 Piyush Raman Srivastava
take care if u use fast exponentiation algorithm ;) |
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2012-05-25 18:37:45 Fringe
coverd evry case still getting wa |