Submit | All submissions | Best solutions | Back to list |
ADATREE - Ada and Trees |
Ada the Ladybug is a farmer. She has a long furrow in which she grows trees. Each tree has some weight. The task is simple, she wants to know the biggest tree on some part of the furrow which is not greater than some height H. As Ada asks for this very often, she asked you to write a program for this.
Input
The first line will contain two integer 1 ≤ N, Q ≤ 3*105, the number trees and the number of questions.
The next line will contain N integers 0 ≤ Ai ≤ 106, the heights of trees.
The sum next Q will contain three integers: 0 ≤ l ≤ r < N, the segment of furrow she is interested in and 0 ≤ H ≤ 106
Output
For each query output either the size of highest tree lesser/equal to H or output 0 if such tree doesn't grow on given segment.
Example Input
9 8 1 5 9 11 9 7 6 2 1 1 6 4 1 6 10 0 8 97 0 8 4 1 4 5 2 6 8 2 8 5 3 3 12
Example Output
0 9 11 2 5 7 2 11
Added by: | Morass |
Date: | 2017-10-08 |
Time limit: | 3s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All |
Resource: | Tunisian Collegiate Training Contest - Round #01 |
hide comments
|
|||||
2022-01-04 05:26:52
For those who are stuck <snip> I tried Mo's algorithm, it won't work (TLE), just saying :) Last edit: 2022-01-05 02:58:01 |
|||||
2021-09-23 10:07:19
persistent segment tree |
|||||
2020-07-27 06:05:00
Handle it as offline query. Sort + segment tree. Great problem! |
|||||
2019-11-22 05:35:23
great problem indeed approach : SegmentTree +mergeSort +binary Search |
|||||
2019-09-11 13:44:59
Great problem!! |
|||||
2019-03-29 15:32:51 DK...
Solutions like O(nsqrt(n)) or O(nlog^2(n)) don't pass for me, I got AC with Persistent segment tree, it could be overkill. Last edit: 2019-03-29 15:36:38 |
|||||
2018-08-12 10:49:22 DOT
Square root decomposition doesn't produce the best time for me, but it does work. Maybe, try tweaking the block sizes and compare the results. Last edit: 2018-08-12 10:50:09 |
|||||
2018-06-28 14:45:46
@rajcoolaryan: Good day to you! Can't say whether it is enough.. I would have guessed it might be, yet all judge solutions are faster than this :'( |
|||||
2018-06-21 06:30:28
square root decmposition tle |
|||||
2017-10-18 23:28:31
@shubham_001: Good day to you. No judge solution uses treap. I could imagine a solution using it, but I don't think it is the "best" way :) Good Luck & Have Nice Day! |