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AMSCO1 - The AMSCO cipher |
Due to A.M.SCOtt in the 19th century, it's an incomplete columnar transposition cipher
with alternating single letters and digraphs. The first entry must be a digraph.
In both even and odd periods the first column and the first row always alternate:
4 | 1 | 3 | 2 | 5 |
IN | C | OM | P | LE |
T | EC | O | LU | M |
NA | R | WI | T | HA |
L | TE | R | NA | T |
IN | G | SI | N | GL |
E | LE | T | TE | R |
SA | N | DD | I | GR |
A | PH | S |
Input
N lines (N<1000)
Each line of the input contains the numeric key (permutation order of the columns)
and a plaintext. Plaintext letters are in [A-Z] only with no punctuation.
The keylength max is 9 and the length of the plaintext is limited to 250.
The last line ends with EOF.
Output
Output consist of exactly N lines of ciphertexts with letters in [A-Z] with no spaces.
Example
Input:
41325 INCOMPLETECOLUMNARWITHALTERNATINGSINGLELETTERSANDDIGRAPHS Output:
CECRTEGLENPHPLUTNANTEIOMOWIRSITDDSINTNALINESAALEMHATGLRGR
Added by: | legrand |
Date: | 2013-02-28 |
Time limit: | 0.108s-1s |
Source limit: | 5000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | ADA95 GAWK BASH C C++ 4.3.2 CPP C99 FORTRAN GO HASK JAVA OCAML PAS-GPC PAS-FPC PERL PIKE PYTHON PYTHON3 PY_NBC RUBY |
Resource: | classical ciphers |
hide comments
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2013-08-15 20:54:52 cho cho
i am always getting wrong answer ... please check my submission id=9846963 =>I see you have it AC now. Last edit: 2013-08-18 09:38:45 |
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2013-06-29 19:19:09 shiv prasad chabarval
@legrand please check my code and tell me where it fails id:9575315 =>same problem in your bad outputs thnx legrand got it :) Last edit: 2013-06-30 17:38:54 |
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2013-06-27 07:06:05 SWOOSH!!!
Please give a test case for which my solution fails... Submission ID 9325790 =>there are \0 inside your bad outputs Last edit: 2013-06-30 08:15:04 |
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2013-06-24 17:38:23 Ouditchya Sinha
@legrand : Thank you for pointing out my mistake, now I can try AMSCO2. This problem was making the interpretation of AMSCO2 difficult. :) |
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2013-06-21 13:06:10 Ouditchya Sinha
Good Question! :) @Rudiger: My AC solution for your testcase 21 ABCDEF gives CFABDE following this scheme - AB C DE F =>the right scheme is Rudiger's one. your solution for this testcase is wrong, but it's not in the testcases. Last edit: 2013-06-22 14:49:53 |
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2013-06-05 07:51:05 Tywan
Why not open to Ruby and other languages? =>It's now open to Ruby and more. Last edit: 2013-06-05 09:36:58 |
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2013-06-05 07:51:05 Atul Kumar Verma
What is the output for 12 ABCD => it's ABDC Last edit: 2013-05-19 15:26:14 |
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2013-06-05 07:51:05 daft_wullie
What is the scheme for even column numbers? e.g. for 21 ABCDEF: AB C D EF? --edit: it is (if it is a testcase). Got AC with this concept. Last edit: 2013-04-09 21:25:37 |
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2013-06-05 07:51:05 Man Mohan Mishra
@legrand: please check , why i am getting wrong answer ..... : ok , found my mistake. AC :) nice problem !! Last edit: 2013-03-12 18:25:44 |
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2013-06-05 07:51:05 Thotsaphon Thanatipanonda
Open Java please =>legrand: That's done. @legrand: Thankssssssss Last edit: 2013-03-09 02:57:48 |