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ANARC05H - Chop Ahoy! Revisited! |
Given a non-empty string composed of digits only, we may group these digits into sub-groups (but maintaining their original order) if, for every sub-group but the last one, the sum of the digits in a sub-group is less than or equal to the sum of the digits in the sub-group immediately on its right. Needless to say, each digit will be in exactly one sub-group.
For example, the string 635 can only be grouped in one sub-group [635] or in two sub-groups as follows: [6-35] (since 6 < 8.) Another example is the string 1117 which can be grouped in one sub-group [1117] or as in the following: [1-117], [1-1-17], [1-11-7], [1-1-1-7], [11-17] and [111-7] but not any more, hence the total number of possibilities is 7.
Write a program that computes the total number of possibilities of such groupings for a given string of digits.
Input
Your program will be tested on a number of test cases. Each test case is specified on a separate line. Each line contains a single string no longer than 25, and is made of decimal digits only.
The end of the test cases is identified by a line made of the word "bye" (without the quotes.) Such line is not part of the test cases.
Output
For each test case, write the result using the following format:
k. n
where k is the test case number (starting at 1) and n is the result of this test case.
Example
Input: 635 1117 9876 bye Output: 1. 2 2. 7 3. 2
Added by: | psetter |
Date: | 2009-07-05 |
Time limit: | 1s-2s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ERL JS-RHINO NODEJS PERL6 VB.NET |
Resource: | ANARC 2005 |
hide comments
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2012-12-15 19:29:47 avinash kumar
i am trying to solve it by recursion with for loop. can i get some bigger test case |
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2012-12-11 04:35:07 rohitjv
very easy dp :) AC in first attempt Last edit: 2012-12-11 04:35:44 |
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2012-09-29 07:52:03 gourav
yipeeeeeeee!! 15th problem now ;) cool |
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2012-06-27 05:33:00 Surya
@ ;) : Max string length is only 25. So its not a matter of time. Even recursion will do without deeping out! |
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2012-06-26 20:15:18 npsabari
Naive Brute Force method is getting AC in 0.00 sec!! |
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2012-06-19 18:35:34 data
easy one:) |
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2012-06-11 07:13:46 Romal Thoppilan
yaah .. just changing gets() to scanf("%s") worked !! |
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2012-05-23 13:24:34 M LOHIT
In test cases lines are ending with "\r\n" (Windows style) instead of '\n'. Don't use gets() to read input. Use scanf(). |
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2011-05-05 01:31:37 Kashyap Krishnakumar
Nice problem. Some submissions in "TEXT" have been accepted. I guess it has to be disabled. Last edit: 2011-05-05 01:33:26 |
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2010-01-20 19:05:00 Jacob
Dodgy white space on the input here too. |