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ANDROUND - AND Rounds |
You are given a cyclic array A having N numbers. In an AND round, each element of the array A is replaced by the bitwise AND of itself, the previous element, and the next element in the array. All operations take place simultaneously. Can you calculate A after K such AND rounds?
Input
The first line contains the number of test cases T (T ≤ 50).
There follow 2T lines, 2 per test case. The first line contains two space separated integers N (3 ≤ N ≤ 20000) and K (1 ≤ K ≤ 1000000000). The next line contains N space separated integers Ai (0 ≤ Ai ≤ 1000000000), which are the initial values of the elements in array A.
Output
Output T lines, one per test case. For each test case, output a space separated list of N integers, specifying the contents of array A after K AND rounds.
Example
Input: 2 3 1 1 2 3 5 100 1 11 111 1111 11111 Output: 0 0 0 1 1 1 1 1
Added by: | Varun Jalan |
Date: | 2010-01-11 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: NODEJS OBJC PERL6 SQLITE VB.NET |
Resource: | Own Problem, used for Codechef Snackdown http://www.codechef.com/ |
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2023-04-01 17:41:11
You don't need segment tree, sparse table anything. Just think how the array changes after every operation. Hint: Solve rotten oranges problem from Leetcode. |
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2021-06-07 15:01:55
Try to solve it with a sparse table also :D I got error with segment tree |
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2020-07-21 23:45:16
good question for beginners. It's not tough if you think for a while :) |
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2020-06-13 19:54:16
comments are really depressing for beginners |
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2020-06-02 22:54:58
The value of N is not greater than 20000. when you solve it using segment tree, you should set the size of tree 4*N not 3*N. because the size of segment tree = 2^ceil(log2(20000))+1 = 65536 = 3.2768 * N ~= 4*N |
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2020-05-23 17:41:06
solved with O(n*32) complexity Last edit: 2020-05-23 17:46:56 |
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2020-04-09 11:23:49
very easy AC in one go!! |
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2020-04-03 08:00:22
NAAN Last edit: 2020-04-03 08:54:07 |
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2020-01-09 17:15:44
oh my god ez problem ac forst got lmao so ez i am vry good tehc O(nlognlognlognlognlognlognlognlognlognlognlognlognlognlognlognlognlognlognlognlognlognlognlognlognlognlognlognlognlognlogn) /s |
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2019-11-01 09:54:42
AC on second go. Yeahezzz |