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APS - Amazing Prime Sequence |
Bablu is very fond of Series and Sequences...
After studying Fibonacci Series in Class IX, he was impressed and he designed his own sequence as follows...
a[0] = a[1] = 0
For n > 1, a[n] = a[n - 1] + f(n), where f(n) is smallest prime factor of n.
He is also very fond of programming and thus made a small program to find a[n], but since he is in Class IX, he is not very good at programming. So, he asks you for help. Your task is to find a[n] for the above sequence....
Input
Your code will be checked for multiple test cases.
First line of Input contains T (≤ 100), the number of test cases.
Next T lines contain a single number N. (1 < N < 107).
Output
Single line containing a[n] i.e. nth number of the sequence for each test case.
Example
Input: 3 2 3 4 Output: 2 5 7
Added by: | c[R]@zY f[R]0G |
Date: | 2013-02-14 |
Time limit: | 1s |
Source limit: | 5000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
hide comments
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2017-06-26 21:17:09
use long long int...very easy |
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2017-05-12 07:48:02 Shubham Jadhav
Use long long. cost me 1 WA :) |
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2017-05-09 20:44:39 ANKIT JAIN
Nice problem .. |
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2017-04-06 20:51:56 arijit pande
Awesome optimisation problem. |
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2017-03-30 08:04:34
And if you use 64 bit signed integers, remember to use "%lld" instead of "%d"...... |
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2017-02-08 04:44:14
My 50th On spoj |
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2016-12-23 21:56:38
AC in one go!!! XD XD Another sieve problem:) #1 on ranks |
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2016-08-21 15:17:31
Answer for 10000000 is 3203714961609 which is greater than the limit of a 32 bit signed integer. You must use long long, cost me a WA. |
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2016-07-31 11:07:56
when legends copy http://www.spoj.com/problems/APS2/ _/\_ |
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2016-07-30 21:26:41
very easy;) |