Submit | All submissions | Best solutions | Back to list |
BPM - Bipartite Permutation |
Given a positive integer N, consider any permutation of all the numbers from 1 to N. It is required to create two partitions, P1 and P2, from these numbers such that |sum(P1) – sum(P2)| is minimum, where sum(X) denotes the summation of all the numbers in partition X. A partition is defined to be a non-empty subset of the permutation. In other words, find the minimum absolute difference between the summation of all the numbers in each partition. Note that you cannot leave out any number, every number from 1 to N must be part of exactly one partition.
1 ≤ T ≤ 1000
2 ≤ N ≤ 109
Bipartite Permutation (Hard)
Input
The first line contains an integer T, denoting the number of test cases. Each of the next subsequent T lines contain a positive integer N.Constraints
Output
For each test case, first print the case number followed by the minimum absolute difference.Sample Input
5 2 3 4 5 6
Sample Output
Case 1: 1 Case 2: 0 Case 3: 0 Case 4: 1 Case 5: 1
Challenge
Try the harder version here:Bipartite Permutation (Hard)
Added by: | sgtlaugh |
Date: | 2019-11-16 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All |
Resource: | Own Problem |
hide comments
2021-09-24 06:10:50 Waseem Ahmed
Can be solved in O(1) time |
|
2021-01-25 21:21:06
easiest one I got AC with O(1) time Last edit: 2021-01-25 21:21:22 |
|
2020-09-06 06:45:33
Nice one. Got me on Case #1 instead of Case 1. |
|
2020-08-12 15:50:41
Amazing! Last edit: 2020-08-13 09:08:16 |
|
2020-06-26 13:57:57 Shubham Jadhav
Nice problem. Last edit: 2020-06-27 00:22:07 |
|
2020-06-24 06:20:17
Can you check whether my logic correct or not? Finally Solved.. Amazing problem. -> Sorry just seeing this. Great work, congrats! Last edit: 2020-07-30 12:52:50 |
|
2020-06-23 00:56:02
nice problem. Can we prove this? -> Sure we can. Is that very hard to prove? Last edit: 2020-06-23 19:43:47 |
|
2020-03-31 20:08:37
my linear solution is giving me TLE how to solve this? -> Obviously, by using something faster than that! Last edit: 2020-04-17 10:18:41 |