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BRCKTS - Brackets |
We will call a bracket word any word constructed out of two sorts of characters: the opening bracket "(" and the closing bracket ")". Among these words we will distinguish correct bracket expressions. These are such bracket words in which the brackets can be matched into pairs such that
- every pair consists of an opening bracket and a closing bracket appearing further in the bracket word
- for every pair the part of the word between the brackets of this pair has equal number of opening and closing brackets
- replacement -- changes the i-th bracket into the opposite one
- check -- if the word is a correct bracket expression
Task
Write a program which
- reads (from standard input) the bracket word and the sequence of operations performed,
- for every check operation determines if the current bracket word is a correct bracket expression,
- writes out the outcome (to standard output).
Input
Ten test cases (given one under another, you have to process all!). Each of the test cases is a series of lines. The first line of a test consists of a single number n (1<=n<=30000) denoting the length of the bracket word. The second line consists of n brackets, not separated by any spaces. The third line consists of a single number m -- the number of operations. Each of the following m lines carries a number k denoting the operation performed. k=0 denotes the check operation, k>0 denotes replacement of k-th bracket by the opposite.
Output
For every test case your program should print a line:
Test i:
where i is replaced by the number of the test
and in the following lines, for every check operation in the i-th test
your program should print a line with the word
YES,
if the current bracket word is a correct bracket expression, and a line
with a word
NO otherwise.
(There should be as many lines as check operations in the test.)
Example
Input: 4 ()(( 4 4 0 2 0 [and 9 test cases more] Output: Test 1: YES NO [and 9 test cases more]Warning: large Input/Output data, be careful with certain languages
Added by: | Adam Dzedzej |
Date: | 2004-06-15 |
Time limit: | 11s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: NODEJS PERL6 VB.NET |
Resource: | Internet Contest Pogromcy Algorytmow(Algorithm Tamers) 2003 Round IV |
hide comments
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2015-06-16 10:44:26 Prismatic
Lol =)) forget to write 'Test i' :)) |
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2015-06-06 08:19:07 xxbloodysantaxx
Dont forget to print that Test 1: |
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2015-05-27 07:36:13 arthur
Use interval tree here. Solved in first attempt using ideas from matrix (0,1) + (1,0) = (0,0) Last edit: 2015-05-28 19:27:49 |
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2015-05-21 21:55:54 Anubhav Gupta
awesome question. finally AC after 8 attempts :D |
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2014-12-04 16:58:50 Aditya Paliwal
@Vaibhav There is an update on the 4th bracket before the first check operation. The word becomes ()() which is clearly a correct expression. |
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2014-11-02 08:15:57 Vaibhav
How is the answer YES for query 1, since there are 2 extra opening brackets and hence, the all-pairs must have a closing bracket condition is not satisfied. Someone please explain. |
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2014-10-09 00:10:28 fresh
never mind i forgot to comment the part of the code that prints the final shape |
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2014-09-20 20:37:27 Archit Jain
very nice q |
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2014-06-22 19:44:56 Shreyansh Gandhi
My 50th :) |
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2014-05-21 05:31:49 Julian Waldby
I think instead of O(n) it is O(mn). |