Submit | All submissions | Best solutions | Back to list |
BYTESM2 - Philosophers Stone |
One of the secret chambers in Hogwarts is full of philosopher’s stones. The floor of the chamber is covered by h × w square tiles, where there are h rows of tiles from front (first row) to back (last row) and w columns of tiles from left to right. Each tile has 1 to 100 stones on it. Harry has to grab as many philosopher’s stones as possible, subject to the following restrictions:
- He starts by choosing any tile in the first row, and collects the philosopher’s stones on that tile. Then, he moves to a tile in the next row, collects the philosopher’s stones on the tile, and so on until he reaches the last row.
- When he moves from one tile to a tile in the next row, he can only move to the tile just below it or diagonally to the left or right.
Input
The first line consists of a single integer T, the number of test cases. In each of the test cases, the first line has two integers. The first integer h (1 <= h <= 100) is the number of rows of tiles on the floor. The second integer w (1 <= w <= 100) is the number of columns of tiles on the floor. Next, there are h lines of inputs. The i-th line of these, specifies the number of philosopher’s stones in each tile of the i-th row from the front. Each line has w integers, where each integer m (0 <= m <= 100) is the number of philosopher’s stones on that tile. The integers are separated by a space character.
Output
The output should consist of T lines, (1 <= T <= 100), one for each test case. Each line consists of a single integer, which is the maximum possible number of philosopher’s stones Harry can grab, in one single trip from the first row to the last row for the corresponding test case.
Example
Input: 1 6 5 3 1 7 4 2 2 1 3 1 1 1 2 2 1 8 2 2 1 5 3 2 1 4 4 4 5 2 7 5 1 Output: 32 //7+1+8+5+4+7=32
Added by: | Paritosh Aggarwal |
Date: | 2009-02-21 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | ADA95 ASM32 BASH BF C CSHARP CPP C99 CLPS LISP sbcl LISP clisp D FORTRAN HASK ICON ICK JAVA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON RUBY SCM guile SCM qobi ST TEXT WHITESPACE |
hide comments
|
||||||||||||||
2015-10-14 08:45:33 vijay meena
Ac in one go ! easy dp just use bottom up |
||||||||||||||
2015-10-13 14:33:06 Akshay Damle
Don't try this in Python. The input format is wrong. |
||||||||||||||
2015-09-17 12:45:12 Abishek
wow .. learning the power of dp with problems like these ...awesome one :) |
||||||||||||||
2015-09-07 21:58:52 Vivek
Very easy problem. Just take care when at the start of row,then can only jump to same col or right col and at the end of row,then can only jump to left col or same col. No DP and No auxiliary space required,although seems like one. |
||||||||||||||
2015-08-28 11:06:06 Surendra
can any one give the other test cases pls |
||||||||||||||
2015-08-27 14:44:31
@iammangod96 comment helps |
||||||||||||||
2015-08-24 19:12:13
TLE coming in java with recursion+memo techique. Is there any other way to reduce time, without using dp? |
||||||||||||||
2015-08-17 14:24:31 Babu
fck points....solving this was fun! |
||||||||||||||
2015-08-16 21:25:08 Asish Panda
Is it because of such weird format that I get NZEC in python 2.7 ? |
||||||||||||||
2015-08-13 17:15:05
My first DP...feels great!! |