CODERE3 - Coder Express 3!!

Mr Durgeshwara was very impressed by Rahul. But now he was in trouble. He has already fixed his daughter's marriage with Thangabali who was the best coder of his town. He got an idea and arranged a contest between Rahul and Thangabali. They have to solve a problem at the same time and whoever solves first will marry Meenamma. Rahul was not such a good coder and was also getting help from Meenamma. Your task is to help Thangabali to solve the problem to create a twist in story.

The problem was that there are large number of building in the town which are of different heights and all the building are in a single line.

You have to find the maximum possible length of the subsequences of buildings which are possible which are first increasing in heights and then decreasing! Please Note: the heights of the building in the subsequences should be strictly increasing and then strictly decreasing.

Input

First line contains an integer T (1 ≤ T ≤ 100) that represents the number of test cases. Then follows the T containing the integer N (1 ≤ N ≤ 1000) specifying the total number of elements and the next line contains the N integers A1, A2, A3 ... An (1 ≤ Ai ≤ 1000)

Output

For each test case, print only one line, the maximum length of such sequence.

Example

Input:
2
10
1 3 5 6 4 8 4 3 2 1
6
8 6 3 4 2 1

Output:
9
5

Explanation

For the first test case the subsequence is : 1 3 5 6 8 4 3 2 1. For the second test case it is : 8 6 4 2 1


Added by:Rajesh Kumar
Date:2013-09-01
Time limit:1s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: ASM64
Resource:AASF - ABV-IIITM PC-01-9-2013

hide comments
2013-11-08 19:43:32 Ouditchya Sinha
Finally AC! Stupid mistake costed me too many WAs. :)
@Shivam Bansal: No, we can't do better than O(n * log(n)).
2013-09-13 07:15:30 Shivam Bansal
is there any linear solution ? I am able to think better than O(nlogn) solution.
2013-09-05 16:25:47 shinchan
can anyone provide me some more test cases..i m getting wrong ans
2013-09-03 09:00:31 fitcat
You could change the judge from Cube to Pyramid.
2013-09-03 09:00:31 c[R]@zY f[R]0G
Easy one..
Since n <= 1000, even n^2 solution could pass..!!!! :)
2013-09-03 09:00:31 Ivan ©ego
Yes, I agree with Miguel
2013-09-03 09:00:31 Miguel Oliveira
You could increase N to 50,000 or 100,000
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