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COMDIV - Number of common divisors |
You will be given T (T ≤ 106) pairs of numbers. All you have to tell is the number of common divisors between the two numbers in each pair.
Input
First line of input: T (Number of test cases)
In next T lines, each have one pair A B (0 < A, B ≤ 106)
Output
One integer describing number of common divisors between two numbers.
Example
Input: 3
100000 100000
12 24
747794 238336 Output: 36
6
2
Added by: | Mir Wasi Ahmed |
Date: | 2010-10-31 |
Time limit: | 0.600s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | Own problem, used in UODA TST |
hide comments
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2015-03-09 23:52:17 Muhammad Annaqeeb
My sumbmision in C++ was accepted in 2014-04-13 in O(sqrt(gcd(a,b)) , now resubmitting the same submission is TLE. Is the limits now harder than a year ago? Is this on purpose or due to upgrades? can anyone confirm this? Last edit: 2015-03-10 03:50:55 |
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2015-02-25 19:51:18 [Lakshman]
What about a new problem with better constraints like 10^14. (Francky) => There's yet a very recent problem with similar method and constraints. So no. (Lakshman)-->Okay No problem. Last edit: 2015-02-26 04:05:21 |
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2015-02-25 18:13:34 deerishi
Accepted 0.15s! Easy one if you know the math!! |
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2015-02-12 09:12:35 tyler_durden
@abdelkarim my solution is O(sqrt(gcd(a,b))) and passed in 0.5 seconds |
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2015-02-05 21:37:41 jaswin kaur
got TLE with cin,cout & for loop AC with printf,scanf & while loop whyyy?? Last edit: 2015-06-24 06:09:04 |
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2015-01-11 12:11:17 Ayon Das
anyone who has done NDIV this is just a nice variation.. AC in one go :) :) |
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2014-08-22 22:44:46 sarelfeniel
Easy problem but I/O is a huge bottleneck. |
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2014-07-12 11:56:53 surayans tiwari(http://bit.ly/1EPzcpv)
after 5 w.a finally accepted in 1.54 sec :D |
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2014-07-11 15:08:39 Kanav Vats
Easy...careless mistake costed me 2 WA :( |
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2014-06-22 18:00:38 Branimir Rièko
Is 0 a divisor?? :) |