COUNT - Another Very Easy Problem! WOW!!!

Background

This problem is somewhat easier than the problem A Very Easy Problem! because of the super long time limit...

Description

Assurance Company of Moving (ACM) is a company of moving things for people. Recently, some schools want to move their computers to another place. So they ask ACM to help them. One school reserves K trucks for moving, and it has N computers to move. In order not to waste the trucks, the school ask ACM to use all the trucks. That is to say, there must be some computers in each truck, and there are no empty trucks. ACM wants to know how many partition schemes exists with moving N computers by K trucks, the ACM ask you to compute the number of different schemes with given N and K. You needn't care with the order. For example N = 7,K = 3, the the following 3 partition instances are regarded as the same one and should be counted as one scheme: "1 1 5","1 5 1","5 1 1". Each truck can carry almost unlimited computers!!

Input

Each line of the input contains two positive integer N (1 ≤ N ≤ 5000) and K (1 ≤ K ≤ N).Input is terminated by a line with N = K = 0 (this case should not be processed).

Output

For each line, output the number of different partition scheme. To avoid big integers, you must output the answer modulo 1988.

Example

Input:
1 1
7 3
0 0

Output:
1
4

Added by:Fudan University Problem Setters
Date:2007-11-03
Time limit:10s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: ASM64 C99 ERL JS-RHINO OBJC SQLITE
Resource:Time limit: 1000 Years! Memory limit: 2000 GB! Acc%: 100%!

hide comments
2019-02-27 17:12:09
ba tashakor az ostade khoobam kianoosh abbasi
2017-09-01 09:29:23
Classical Dp...learnt so much from this question
2017-08-24 07:49:59
@nap11, possibilities are - 1,1,5; 1,2,4; 1,3,3; and 2,2,3.
2017-07-22 14:12:16
AC in one go!
a real easy problem!
2016-11-16 19:29:34
solved in both top down and bottom up :D
2016-01-12 22:45:46 Bhuvnesh Jain
1d dp solution with O(n^2)

Last edit: 2016-01-12 22:46:13
2015-12-09 00:04:04 Utkarsh Agarwal
Too harsh for python codes. C++ gets accepted in .92 sec. python is atleast 10 times slower than c/c++.
2015-07-09 21:58:55 xxbloodysantaxx
Yet another nice DP problem
2015-06-29 10:07:19 nap11
plz tell me how it will be 4 for n=7 and k=3?


Last edit: 2015-06-29 15:28:19
2014-09-14 13:42:55 Bharath Reddy
Looking at the comments helped me arrive at the right algorithm :) Awesome problem though.

Last edit: 2014-09-14 13:43:11
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