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CRZYSMKR - Crazy Smoker |
The "BHAI Group" Of IIIT Allahabad is Famous For Many Things, Leading in Every Field Of College Activity
So One Day The Leader Of Bhai Group decided to smoke C(N) cigarettes each day:
- F(N) = 34^N+ (30 x N) + 32
- C(N) = F(N) mod (11), where x mod y is the remainder obtained by dividing x by y.
But Bhai Group's Leader's Girlfriend wants that he doesn't smoke any cigarette, so she made modifications:
- F(N) = 34^N+ (30 x N) + (32 + M)
- C(N) = F(N) mod (11)
Edit 1 : Time limit set to 0.100s
Problem Credits : IIIT Allahabad HE Club
Input
First line of each test case is an integer T, total number of test cases. Next T lines contains a single integer N.
Output
Print the minimum value of M in single line for each test case.
Constraints
1 <= T <= 10^6
1 <= N <= 10^18
Example
Input: 2 1 2 Output: 3 6
Explanation:
For N = 1 F(N) = 34 + 30 + 32 = 96 So, M = 3 Now, C(N) = 99 mod(11) = 0 For N = 2 F(N) = 1156 + 60 + 32 = 1248 So, M = 6 Now, C(N) = 1254 mod(11) = 0
Added by: | Siddharth Singh |
Date: | 2016-02-10 |
Time limit: | 0.100s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 GOSU JS-MONKEY |
Resource: | HackerEarth Contest Of IIIT Allahabad |
hide comments
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2016-07-25 22:47:31
easy one ...but nice mathematics is involved try to break the problem into parts |
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2016-07-13 07:33:23
nice question |
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2016-07-12 22:22:48
Here comes my century!! 2 lines of python is enough! |
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2016-06-21 19:00:40
done it without any modular exponentiation , simple concept of binomial expansion :) gives you a linear equation to check :D |
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2016-05-15 08:32:40 SUBHAJIT GORAI
Thanks @Murad Al Wajed ,I too made the same mistake and it costed me two WA's . :) |
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2016-04-24 10:59:57 Murad Al Wajed
when C(N)= 0 result will 0. This shit cost me 4 WA |
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2016-03-01 10:27:38
this is awesome...... |
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2016-02-20 06:53:22 Abhishek Kumar Singh
For those who know Remainder theorem, this is a 6 line code in C/C++. |
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2016-02-19 19:59:32 Ankit
This was mathematics. :D Got it in the 2nd attmept. :) |
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2016-02-17 18:24:04 pvkcse
@divyanshu01 yes there is... haven't you heard about pow() in python with three arguments? pow(base,exp,modulus). Hope it helps! @Farhan764 Thanks!! you saved me from more WA's! Last edit: 2016-02-17 18:25:52 |