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CZ_PROB1 - Summing to a Square Prime |
$S_{P2} = \{p \mid p: \mathrm{prime} \wedge (\exists x_1, x_2 \in \mathbb{Z}, p = x_1^2 + x_2^2) \}$ is the set of all primes that can be represented as the sum of two squares. The function $S_{P2}(n)$ gives the $n$th prime number from the set $S_{P2}$. Now, given two integers $n$ ($0 < n < 501$) and $k$ ($0 < k < 4$), find $p(S_{P2}(n), k)$ where $p(a, b)$ gives the number of unordered ways to sum to the given total ‘$a$’ with ‘$b$’ as its largest possible part. For example: $p(5, 2) = 3$ (i.e. $2+2+1$, $2+1+1+1$, and $1+1+1+1+1$). Here $5$ is the total with $2$ as its largest possible part.
Input
The first line gives the number of test cases $T$ followed by $T$ lines of integer pairs, $n$ and $k$.
Constraints
- $0 < T < 501$
- $0 < n < 501$
- $1 < S_{P2}(n) < 7994$
- $0 < k < 4$
Output
The $p(S_{P2}(n), k)$ for each $n$ and $k$. Append a newline character to every test cases’ answer.
Example
Input: 3 2 2 3 2 5 3 Output: 3 7 85
Added by: | Rahul |
Date: | 2007-03-10 |
Time limit: | 1s |
Source limit: | 3000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ERL JS-RHINO NODEJS PERL6 VB.NET |
Resource: | Sam Collins |
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2011-09-06 23:36:18 Mitch Schwartz
Suggest changing "with ‘b’ as its largest part" to "with ‘b’ as its largest possible part" and similarly for "with 2 as the largest part". Last edit: 2011-09-07 00:56:41 |