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DCOWS - Dancing Cows |
It's the spring dance and, in a rare occurrence, the N (1 ≤ N ≤ 5000) bulls have been invited to dance with the M (N < M ≤ 5000) cows (as long as they stay on their very best behavior).
Farmer John, almost obsessive-compulsive in his organization of dances, wants the spectacle to be as visually attractive as possible. Thus, he wants to pair up the N bulls with cow partners such that the total of all the magnitudes of differences in height is minimized. Bulls have heights B_i (1 ≤ B_i ≤ 1,000,000) and cows have height C_i (1 ≤ C_i ≤ 1,000,000). Of course, some cows will be unmatched since N-M of them will have no partners; ignore their heights.
Input
- Line 1: Two space-separated integers: N and M.
- Lines 2..N+1: Line i+1 contains a single integer: B_i.
- Lines N+2..M+N+1: Line i+N+1 contains a single integer: C_i.
Output
- Line 1: A single integer that is the minimum of the sum of the absolute value of the height differences that can be achieved.
Sample
Input: 5 7 10 16 12 10 13 7 17 12 10 9 6 11 Input: 4
Explanation
There are five bulls + seven cows with various heights:
- Bulls: 10 10 12 13 16
- Cows: 6 7 9 10 11 12 17
Here is one way to achieve a total difference of 4:
- Bulls: 10 10 12 13 16
- Cows: 9 10 11 12 17, with 6 7 unmatched.
Added by: | Se7s |
Date: | 2013-05-15 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ADA95 ASM32 ASM64 GAWK BASH BF CLPS CLOJURE LISP sbcl LISP clisp D ERL FSHARP GO ICON ICK LUA NEM NICE NODEJS OCAML PERL6 PIKE PRLG-swi SCALA SCM guile SCM qobi SED ST TCL WHITESPACE |
Resource: | USACO 2008 Gold |
hide comments
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2020-04-17 11:20:23
good problem =))))) from 2020 with luv |
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2018-06-17 22:02:19
pretty simple.Just a lot of WA due to limiting value. try something in the order of 10^12 |
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2017-09-21 14:38:10
Do you have to consider the case N>M ? |
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2017-08-30 09:10:20
@awesome_me the possible answer can be as large as 5000*10^6, so make sure your limiting variable is at least that big. |
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2017-06-23 12:03:23
Those getting wa also check for the case when n = m :) |
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2017-06-02 21:29:58
make sure you are taking min variable long enough to handle all values in dp array(hint for those who are getting WA on test case 15) Last edit: 2017-06-02 21:56:11 |
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2017-05-28 22:39:42 Sigma Kappa
Somehow my assert (m > n) failed, but never mind, got Accepted with O(n^2). Does not look like Gold problem at all, hmm... |
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2017-03-27 08:55:05
take dp array as long long int!! |
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2016-12-08 17:15:51
@theph0enix : Greedy approach will not work when a bull has two choices of pairing with same height difference on different sides. i.e a Bull of height H has a choice to pair with two cows of height H-d and H+d . You will never know which choice will give you optimal solution. |
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2016-07-19 10:18:25
Why doesn't the greedy approach work here? |