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DIV2 - Divisors 2 |
Let N be a positive integer and d(N) be the number of positive divisors of N including 1 and N. Your task is to compute all N in [1,10^6] for which d(N)>3 and if M divides N then d(M) divides d(N) too.
Input
None.
Output
To make the problem less output related write out only every 108-th of them, one per line.
Example
Output: 267 511 753 ... 999579 999781 999977
Added by: | czylabsonasa |
Date: | 2005-05-24 |
Time limit: | 1s |
Source limit: | 3333B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All |
Resource: | Folklore |
hide comments
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2016-09-04 23:05:38 Anuj Arora
Similar to DIV ....just pattern observation in the output |
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2016-08-11 19:15:22 Sunny
I tried running a loop from square root of a number to its half, counting 2 for each factor and storing the factors and so on as well as storing d(N) for all values starting from 1 to 1000000. I am getting a TLE. |
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2016-07-14 14:15:23 Piyush Kumar
For people confused about M, M divides N, so M is a divisor of N. |
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2016-06-08 00:06:49
can anybody explain what is M? Last edit: 2016-06-08 00:07:14 |
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2015-12-12 21:24:12
What is M? |
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2015-01-23 18:04:00 Sayak Haldar
this problem is awesome...:) |
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2014-11-14 17:52:49 Francky
Note for archive : this problem was on Pyramid before this day, now on cube. EB don't have hands on those changes. |
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2014-09-14 14:17:24 Bharath Reddy
Clever problem. Easy to implement... |
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2011-09-08 20:24:25 যোবায়ের
M divides N ==> N % M = 0 |