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DIVCNT3 - Counting Divisors (cube) |
Let be the number of positive divisors of .
For example, , and .
Let
Given , find .
Input
First line contains (), the number of test cases.
Each of the next lines contains a single integer . ()
Output
For each number , output a single line containing .
Example
Input
5
1
2
3
10
100
Output
1
5
9
73
2302
Explanation for Input
-
Information
There are 5 Input files.
- Input #1: , TL = 1s.
- Input #2: , TL = 20s.
- Input #3: , TL = 20s.
- Input #4: , TL = 20s.
- Input #5: , TL = 20s.
My C++ solution runs in 7.1 sec. (total time)
Source Limit is 12 KB.
Added by: | Min_25 |
Date: | 2014-06-29 |
Time limit: | 1s-20s |
Source limit: | 12288B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 GOSU |
hide comments
2018-01-11 17:40:23 Min_25
@zimpha: Probably, my solution runs in time (and uses a similar formula as yours). Your solution will run faster than mine if it uses "int64 u = nd / (a * a);" (or "int64 u = nd / (double)(a * a);") on line 74. Last edit: 2018-01-11 17:58:20 |
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2018-01-11 15:33:31 zimpha
@Min_25, what is the time complexity of your solution. I use an O(n^(2/3)) method, but I still cannot run as fast as you can. |
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2015-01-17 20:30:17 Abhay Pratap
compiler was running up to case 5, then showed time limit exceeded...does it means only case 5 is not in the time_limit? |
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2014-10-19 11:11:41 TURTLE
@Min_25- Please give some hints about the question. Its been a while and the question is yet unsolved! Thanks in advance. --Min_25--> The Dirichlet convolution is the key to DIVCNT2 <s>and DIVCNT3</s>. Last edit: 2016-05-20 09:58:46 |