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EIGHTS - Triple Fat Ladies |
Pattern Matchers have been designed for various sorts of patterns. Mr. HKP likes to observe patterns in numbers. After completing his extensive research on the squares of numbers, he has moved on to cubes. Now he wants to know all numbers whose cube ends in 888.
Given a number k, help Mr. HKP find the kth number (indexed from 1) whose cube ends in 888.
Input
The first line of the input contains an integer t, the number of test cases. t test cases follow.
Each test case consists of a single line containing a single integer k (1 <= k <= 2000000000000).
Output
For each test case, output a single integer which denotes the kth number whose cube ends in 888. The result will be less than 263.
Example
Input: 1 1 Output: 192
Added by: | Matthew Reeder |
Date: | 2006-10-30 |
Time limit: | 1.197s |
Source limit: | 30000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ERL JS-RHINO NODEJS PERL6 VB.NET |
Resource: | Al-Khawarizm 2006 |
hide comments
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2018-02-19 05:13:28
if k == 1 then 192 else 192 + (k-1)*250 |
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2018-01-23 13:41:18
Total time waste -_- |
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2018-01-17 14:41:30
its simple, number of the this form 10(19+25(k-1))+2. you can deduce this if you see the example carefully |
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2018-01-11 17:06:02
Use Spoj Toolkit thanks to @ajayc1007 and @prasad_235 |
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2017-12-29 07:19:27
Nobody asks you to write AC in one go bitches..!! Please dont spam here #admin |
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2017-12-22 22:50:24
Shut up, anybody wants know your solutions! Last edit: 2017-12-22 22:50:51 |
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2017-12-19 15:04:10
look for using AP(ARITHMATIC PROGRESSION) in the problem. |
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2017-12-18 14:16:39
AC in one go.......... |
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2017-12-06 19:38:31
AC in one go |
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2017-11-14 07:37:16
1 line of code in python |