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FACTDIV - Factorial and divisorss |
You have given number of test cases.
Each test case have two space separated integer L and R. You have to find total value of fun(L) + fun(L+1) + ... + fun(R), where fun(x) is total number of positive divisors of x factorial. Since result may be large print it modulo 1000000007.
Input
First line of input contains T total number of test case.
Next T lines contain two space-separated integers L and R.
1 <= T <= 1000000
1 <= L <= R <= 1000000
Output
For each test case output the result modulo 1000000007.
Example
Input: 10
1 9
6 7
2 4
7 8
1 3
10 10
3 5
6 7
1 10
6 6 Output: 377
90
14
156
7
270
28
90
647
30
Added by: | ashish kumar |
Date: | 2016-03-17 |
Time limit: | 1s-2.5s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 GOSU JS-MONKEY |
Resource: | self |
hide comments
2018-09-13 23:44:05
Great problem. Prototyped in PyPy, precalc ran at 1.64s using BACTERIA; same program translated to C couldn't even precompute 50000 in the same time. Went cycling, had some sleep, figured out what needs to be done -- C solution speeded up 100+ times and subsequently ACd, yet PyPy now runs at 2.23s. Don't understand the world anymore... |
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2017-01-16 16:28:51
any hint..? |
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2016-05-27 08:31:55 Nishant Gupta
Nice one :) |
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2016-03-22 16:26:19 [Lakshman]
what is the expected complexity? |