Submit | All submissions | Best solutions | Back to list |
GCDEX - GCD Extreme |
Given the value of N, you will have to find the value of G. The meaning of G is given in the following code
G = 0; for (i = 1; i < N; i++) for (j = i+1; j <= N; j++) G += gcd(i, j);Here gcd() is a function that finds the greatest common divisor of the two input numbers.
Input
The input file contains at most 20000 lines of inputs. Each line contains an integer N (1 < N < 1000001). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero.
Output
For each line of input produce one line of output. This line contains the value of G for the corresponding N. The value of G will fit in a 64-bit signed integer.
Example
Input: 10 100 200000 0 Output: 67 13015 143295493160
Time limit has been changed. Some AC solutions get TLE.
Added by: | Phenomenal |
Date: | 2009-02-16 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ERL JS-RHINO NODEJS PERL6 VB.NET |
Resource: | ACM World Final Warm up 1 - 2008 |
hide comments
|
||||||||
2024-10-08 16:09:33
+2 hours tl cause using #define int long long |
||||||||
2024-05-16 08:26:40
Check proof of Gauss Theorem related to Euler's Totient's Function this problem would be cakewalk, only thing would be clever implementation to pass the strict TL. |
||||||||
2023-03-08 07:07:32
such a nice problem of euler totient function concept |
||||||||
2022-08-29 20:16:00
It honestly feels so good to get AC in the first attempt on this one XD Anyways, for those who are struggling, here's my solution: <snip> Concepts: Euler Totient + Sieve. (P.S try to pre-compute your answer to avoid tle) [Simes]: No thanks, we don't want links to solutions. @Simes Sorry for that will keep it in mind henceforth! Last edit: 2022-08-30 13:19:33 |
||||||||
2021-07-09 20:33:31
WA |
||||||||
2021-06-28 06:07:04
Totient Function + Sieve concept Nice problem :D |
||||||||
2020-07-09 12:24:14
Time limit is too strict although AC in 2 GO!! precalculate all divisors of numbers upto given range |
||||||||
2020-04-25 11:47:19
I used euler Totient function.....and getting runtime (SIGSEV) , can anyone help me here? |
||||||||
2019-05-12 16:21:48
modified sieve and totient function..... AC :) |
||||||||
2019-03-16 15:13:43 DK...
Try to compute everything into arrays, using vector's push_back function makes TL |