GIRLSNBS - Girls and Boys

There are G girl students and B boy students in a class that is about to graduate. You need to arrange them in a single row for the graduation. To give a better impression of diversity, you want to avoid having too many girls or too many boys seating consecutively. You decided to arrange the students in order to minimize the gender regularity. The gender regularity of an arrangement is the maximum number of students of the same gender (all girls or all boys) that appear consecutively. Given G and B, calculate the minimum gender regularity among all possible arrangements.

Input

Each test case is described using a single line. The line contains two integers G and B representing the number of girls and boys in the class, respectively (0 ≤ G, B ≤ 1000). The end of input is indicated with a line containing the number −1 twice.

Output

For each test case, output a single line with a single integer representing the minimum gender regularity that an arrangement of G girls and B boys can have.

Example

Input: 
10 10
5 1
0 1000
-1 -1
Output:
1
3
1000

Added by:Pablo Ariel Heiber
Date:2010-09-27
Time limit:2s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: ASM64 NODEJS OBJC VB.NET
Resource:FCEyN UBA ICPC Selection 2010

hide comments
2017-05-29 23:29:48
Simple pigeonhole principle!!
2017-04-23 09:05:53
AC in one go .., Just paper work needed ..,
2017-03-22 20:22:44
Nothing much....Just a little thinking... be practical... :P
2017-03-17 16:30:14 shiv pratap singh
very simple problem just we have to do division

Last edit: 2017-03-17 16:30:32
2017-03-09 19:12:50
Test Case (0,0) cost me two WA's...nice one
2017-03-04 18:47:00
It looked tough initially to me.Thought that required combinatrics . Finally turned out to be an adhoc. Nice logic a bit of brainstorming required.
2017-02-14 09:01:02
Beware of cases where a and b is 0
2017-01-05 15:59:39
beware of the permutations, nice logic :)
2016-12-07 17:20:47
@baadshah_ i passed all your test case but still I got WA. :-(
2016-11-27 08:25:38
Easy one. Read it second time. Got in less than 5 minutes. AC in a go.
No need to use floating point numbers or ceil() function.
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