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GNY07C - Encoding |
Chip and Dale have devised an encryption method to hide their (written) text messages. They first agree secretly on two numbers that will be used as the number of rows (R) and columns (C) in a matrix. The sender encodes an intermediate format using the following rules:
- The text is formed with uppercase letters [A-Z] and <space>.
- Each text character will be represented by decimal values as follows:
<space> = 0, A = 1, B = 2, C = 3, ..., Y = 25, Z = 26
The sender enters the 5 digit binary representation of the characters’ values in a spiral pattern along the matrix as shown below. The matrix is padded out with zeroes (0) to fill the matrix completely. For example, if the text to encode is: "ACM" and R=4 and C=4, the matrix would be filled in as follows:
A = 00001, C = 00011, M = 01101 (one extra 0)
The bits in the matrix are then concatenated together in row major order and sent to the receiver. The example above would be encoded as: 0000110100101100
Input
The first line of input contains a single integer N, (1 ≤ N ≤ 1000) which is the number of datasets that follow.
Each dataset consists of a single line of input containing R (1<=R<=20), a space, C (1<=C<=20), a space, and a text string consisting of uppercase letters [A-Z] and <space>. The length of the text string is guaranteed to be <= (R*C)/5.
Output
For each dataset, you should generate one line of output with the following values: The dataset number as a decimal integer (start counting at one), a space, and a string of binary digits (R*C) long describing the encoded text. The binary string represents the values used to fill in the matrix in row- major order. You may have to fill out the matrix with zeroes (0) to complete the matrix.
Example
Input: 4 4 4 ACM 5 2 HI 2 6 HI 5 5 HI HO Output: 1 0000110100101100 2 0110000010 3 010000001001 4 0100001000011010110000010
Added by: | Marco Gallotta |
Date: | 2008-03-11 |
Time limit: | 14.95s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ERL JS-RHINO NODEJS PERL6 VB.NET |
Resource: | ACM Greater New York Regionals 2007 |
hide comments
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2015-05-27 16:18:51 Shubham Jadhav
not able to see the image :( |
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2015-01-07 17:27:01 vijay
it is giving TLE. Don't know the reason.. plzzz suggest some optimization ... link is <snip> Last edit: 2022-11-25 20:32:48 |
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2014-06-15 03:54:16 Ritesh
nice problem .. Don't worry about the padding .. LOL !! @Rachmawan thank you for the test case .. |
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2013-06-26 13:35:51 Erti-Chris Eelmaa
This judge is really picky! It was fun problem. Spiral generating is tricky hehe :-) |
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2013-02-19 15:43:53 killerz
good problem !!! |
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2013-01-27 18:00:29 Ankur Rastogi
@Navneet, bt problem says 1<=R,C<=20 i am also getting SIGABRT error, please help. Last edit: 2013-01-27 18:05:15 |
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2012-06-23 22:25:07 Navneet Yadav
one of the test case is also of the form <no of rows><space><no of columns><ENTER> do take care of that..!! Last edit: 2012-06-24 19:56:51 |
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2012-01-01 08:20:17 Abhra
the code is running fine in my system for all boundary conditions, but am getting segmentation fault here.... pls check submission #6277526 |
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2011-10-17 18:22:28 Hazem
my program output the same of test case and 5 5 <space> is correct why WA why ?????? |
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2010-11-24 06:44:20 Rachmawan Atmaji Perdana
Take care of this test case : 5 5 <space> |