GSS1 - Can you answer these queries I

You are given a sequence A[1], A[2] ... A[N] . ( |A[i]| ≤ 15007 , 1 ≤ N ≤ 50000 ). A query is defined as follows:
Query(x, y) = Max { a[i] + a[i+1] + ... + a[j] ; x ≤ i ≤ j ≤ y }.
Given M queries, your program must output the results of these queries.

Input

  • The first line of the input file contains the integer N.
  • In the second line, N numbers follow.
  • The third line contains the integer M.
  • M lines follow, where line i contains 2 numbers xi and yi.

Output

Your program should output the results of the M queries, one query per line.

Example

Input:
3 
-1 2 3
1
1 2

Output:
2

Added by:Nguyen Dinh Tu
Date:2006-11-01
Time limit:1s
Source limit:5000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: ERL JS-RHINO NODEJS PERL6 VB.NET

hide comments
2016-05-11 15:43:27
Did anyone use Treap to solve this problem?
I keep getting TLE using Treap...(sad...)
2016-05-02 08:34:46
同意楼上!!
2016-05-01 05:38:06
TL is too strict
2016-04-14 15:04:18 geekyadity
Use printf, scanf. ( sync_with_stdio(false) ) gives TLE with the same code
2016-04-10 09:16:53
yoo..!! after 2 WA and 2 TLE finally accepted. To get AC from TLE just changed input array and tree into global.
2016-02-14 14:50:58 minhthai
why hate java so much :((
for once, please increase the time limit for java
2016-02-12 13:51:16 Tomasz Plaskota
as mentioned before: make sure you use fast input output cause there is ALOT of that.
Also to earlier questions: maximum of subarray algorithm works in general but you will still find it too slow for amount of queries M that test cases provide (even fastest MSA is O(N*M), while ST will be O(N*1))
2016-02-05 14:27:47
FOR JAVA GUYS :
USE fast input reader for ip
USe stringbiulder to store op and print all at once at the end
And maybe some optimizations inside
2016-01-25 10:38:20 nib
Extremely strict TL. Same idea using struct passed, but using vector gets TLE :/
2016-01-18 17:09:32
The problem requires fast input/output, I had a TLE even with sync_with_stdio(false) and tie(0)
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