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HACKRNDM - Hacking the random number generator |
You recently wrote a random number generator code for a web application and now you notice that some cracker has cracked it. It now gives numbers at a difference of some given value k more predominantly. You being a hacker decide to write a code that will take in n numbers as input and a value k and find the total number of pairs of numbers whose absolute difference is equal to k, in order to assist you in your random number generator testing.
NOTE: All values fit in the range of a signed integer, n, k>=1
Input
1st line contains n & k.
2nd line contains n numbers of the set. All the n numbers are assured to be distinct.
(Edited: n <= 10^5)
Output
One integer saying the no of pairs of numbers that have a diff k.
Example
Input: 5 2
1 5 3 4 2 Output: 3
Added by: | vijay |
Date: | 2011-10-15 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | Own Problem |
hide comments
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2015-08-02 20:51:14 hrishabh
binary search..;) |
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2015-07-27 19:52:08 Vaporeon
easy :) |
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2015-07-25 19:05:58 Anurag Sharma
Merge sort + binary search =AC in one go...... should be considered as tutorial problem.... only for dummies :P |
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2015-07-20 22:38:00 Varun Gambhir
STL rocks! :) |
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2015-06-29 03:51:53 SangKuan
ok,i knowed how to do in O(n)... |
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2015-06-29 03:48:51 SangKuan
O((n+1)logn) ac.who can tell me how to do O(n)? |
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2015-06-09 19:21:25 PRIBAN91
Java users be very careful! Try to write your own parsing class with less buffer space. Nice problem to judge your skill and depth in the knowledge of Java. |
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2015-06-04 20:01:56 Rahul Jain
no need of binary search.. sorting+one scan of array is sufficient. i.e O(nlogn + n) |
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2015-06-03 10:30:24 harshit sharma
easy binary search.. :) weak test cases... |
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2015-05-19 08:32:53 kartikay singh
merge sort+binary search ==> AC:) |