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HAPPINESS - Happiness |
You are given an array on N elements a[1], a[2], a[3], ... a[N].
Now you will have to answer some queries.
In every query, you will be given an interval, [l, r]. For this interval you have to print the total summation of happiness of all the elements of the given array between the interval [l, r].
The happiness of an element a[i] between interval [l, r] is: the number of sub-array [lj, rj] where the minimum value between [lj, rj] is equal to a[i]. Here, l <= lj <= i and i <= rj <= r.
Now, you have to print the total summation of happiness of all the elements between [l, r].
Input
The first line of the input contains the number of test cases T. The first line of each test case contains two numbers, N and M. N is the number of elements in array a and M is the number of queries you need to perform.
The next line contains N integers, the array a: a[1], a[2], a[3], ... a[N].
Next M lines contains two integers, l and r.
Constraints
1 <= T <= 5
1 <= N, M <= 50000
1 <= a[i] <= 1000000000
1 <= l <= r <= N
Output
For each test case, you need to print the case number on the first line in this format: Case X: where X is the case number.
In the next M lines, you need to print the total summation of happiness of all the elements between [l, r] of the given array.
Example
Input: 2
5 2
1 3 2 4 3
1 3
2 4
5 2
5 3 7 6 8
1 4
2 5 Output: Case 1:
6
6
Case 2:
10
10
Problem Setter: Raihat Zaman Neloy. Used in Eid 2016 contest. For more about Eid 2016 contest: Click Here
Added by: | Raihat Zaman Neloy |
Date: | 2016-07-22 |
Time limit: | 1s-5s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 GOSU |
hide comments
2016-08-07 17:36:06 kataria
WTF |
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2016-07-29 08:41:09
I think so that all elements are not distinct Last edit: 2016-07-29 08:41:40 |
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2016-07-26 16:25:28 Mitch Schwartz
@problem setter: Note that the challenge section is for problems with special scoring. Last edit: 2016-07-26 17:53:19 |
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2016-07-22 15:42:18 Francky
What is the challenge ? Maybe the best place is classical section. |