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IITD5 - Expected Cycle Sums |
We are given a sequence S of N distinct integers. Denote by S[i] as ith element of S.
Hardik picks up a random permutation of S , breaks it into product of disjoint cycles & looks at cycle containing S[i].He notes down the sum of all element of this cycle. Call the expected value of this sum as cycleSum[i]. Your task is to find the minimum value amongst all cycleSums.
Assume all permutations of these N numbers are equally likely.
Input Format :
First line contains an integer T which denotes the number of test cases. Then follow description of T test scenarios. Each test scenario takes 2 lines. First line contains a single integer N, the size of S. Then follows second line containing N elements of S.
Output Format :
Print answer for each test case , rounded to exactly one decimal place , in one line each.
Sample Input :
2
1
1
2
1 2
Sample Output:
1.0
2.0
Note: Notion of cycles for any sequence is defined by using index in the sequence (1-N).
Explaination for sample output :
In first case only possible permutation is (1) So answer is trivially 1.0
In second case possible permutations are (1)(2) & (12). As both of these are equally likely, cycleSum[1] = 1/2 * 1 + 1/2 * (1+2) = 2.0
And cycleSum[2] = 1/2 * 2 + 1/2 * (1+2) = 2.5. Smaller of these is 2.0 , hence the answer.
Constraints :
1<=T<=500
1<=N<=5000
All elements of S are distinct integers in range 0 to 10^5
Added by: | Nikhil Garg |
Date: | 2010-10-15 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 NODEJS OBJC VB.NET |
Resource: | own problem, used for IIT Delhi ACM ICPC provincial contest 2010 |
hide comments
2014-07-28 23:22:34 Saurabh Jain
How the possible permutations are (1),(2) or (12) shouldn't it be 1,2 and 2,1 |
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2010-10-23 17:24:56 Nikhil Garg
@TheChamp - No where in the problem it is written that permutation would be broken in only 2 disjoint cycles. |
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2010-10-23 17:22:16 The Champ
the test cases leave an ambiguity, will that permutation of S be broken into disjoints of only two sets. for example, s=1,2,3,4 so is (1)(2)(3,4) allowed since there are three disjoint sets |