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ILD18ACP - Count Pairs |
Given a undirected graph with n vertices and m edges. Your task is count the number of distinct pairs (u, v) that there is exist a path with length exactly 2 from u to v. Another mean, with each pair (u, v), we could find a vertex t that we have an edge (u, t) and (t, v). The input set may be contains multiple edge between any vertex and not consider to connected.
Input
- First line: n, m (1 <= n, m <= 10^5).
- m following line: u, v (1 <= u, v <= n).
Output
The number of distinct pairs.
Example
Input: 5 4
2 1
1 5
3 1
4 3
Output: 4
Note: we have (1, 4), (2, 3), (2, 5), (3, 5)
Added by: | Gầy :)) |
Date: | 2018-11-16 |
Time limit: | 1s-3s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All |
hide comments
2022-02-18 09:18:12
Don't forget the cases of self loop,, and use bitsets. |
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2020-06-01 23:58:00 Scape
Great problem. Just to clarify, path implies shortest path here. So the answer to @feodorv's test case would be 0. |
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2020-03-30 00:49:03
What is the answer for the following graph: 2 2 1 2 1 2 ? |