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MAY99_3 - Easy Jug |
One day Manku was very thirsty so he decided to drink exactly z litres of water. However , in front of him, there is a well of infinite amount of water and 2 empty jugs of quantity x litres and y litres respectively.
Now Manku can do the following operations to any jug
- Fill it completely from the well
- Empty it entirely
- Transfer as much water from Jug 1 to Jug 2, until Jug 1 gets empty or Jug 2 is completely filled.
Now since he has no measuring device so he will do these operations only to make any of the 2 jug having exactly z litres of water.
Now Your task is given value of x, y, z, tell whether it is possible for Manku to drink water or not.
Input
First Line of Input contains T, the number of test cases. (T <= 25)
Then for each test case there are 3 numbers x, y, z given in separate line.
- 1 <= x <= 10^8
- 1 <= y <= 10^8
- 1 <= z <= 10^8
Output
For each test case outputĀ "YES" if manku can drink exactly z litres of water else "NO".
Example
Input: 5 2 4 3 2 5 1 9 3 6 3 8 7 6 1 10 Output: NO YES YES YES NO
Explanation
- In Test case 1 Either Manku can have 2 or 4 litres of water so he cant drink 3 litres.
- In Test case 2 Manku can have 1 litre water by doing the following operations:
- Fill 2 litre Jug
- Transfer its water to 5 litre Jug
- Again Fill 2 litre Jug
- Again Transfer its entire water to 5 litre Jug
- Now 5 litre Jug will have total 4 litre water
- Again Fill 2 litre Jug
- Now transfer 1 litre water to 5 litre Jug
- because at present 5 litre Jug don't have space for more than 1 litre water
- Now the 2 litre Jug will have only 1 litre water left
- For Test case 3 we will transfer 3 litre water twice from 3 litre jug to 9 litre jug
- For test Case 4,
- transfer 3 times water of 3 litre jug to 8 litre jug
- Ultimately 3 litre Jug has 1 litre water left and 8 litre Jug is full
- Now empty 8 litre jug and pour remaining 1 litre of 3 litre jug in it
- Now fill 3 litre jug fully twice and transfer its water to 8 litre jug
- Now 8 litre Jug will have 7 litre water
- For Test case 5, we cant have 10 litre of water in any jug
Added by: | Mayank Tuteja |
Date: | 2013-01-17 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | ASM32-GCC MAWK BC C-CLANG C NCSHARP C++ 4.3.2 CPP CPP14 CPP14-CLANG COBOL COFFEE D-CLANG D-DMD DART ELIXIR FANTOM FORTH GOSU GRV JAVA JS-MONKEY JULIA KTLN NIM OBJC OBJC-CLANG OCT PICO PROLOG PYPY PYPY3 R RACKET RUST CHICKEN SQLITE SWIFT UNLAMBDA VB.NET |
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2017-06-29 13:55:16
using gcd , it will be easy for solving this question. |
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2017-03-17 19:07:29
3289 82394 1 why answer is no for this |
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2016-08-18 21:35:42
legendary advise..UNDERSTAND EVERY LINE OF PROBLEM CAREFULLY....AND THEN AFTER TAKE THESE TYPES OF COMMENTS VERY SERIOUSLY.... |
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2016-06-12 10:05:17
little corner case modification to CEQU and AC! |
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2016-01-25 08:50:28
Prerequisites : Diophantine equation and Extended euclids algo. :) |
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2015-12-10 13:49:35
too easy if the logic strikes in your mind |
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2015-10-20 17:16:44
AC in one go had to think a lot about the logic |
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2015-09-26 19:55:41 rahul_verma
same as CEQU just copy the code and change output format got AC!!! |
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2015-09-26 15:09:59 Kaustubh Mallik
@hello_word @Kushal Saharan: Read the question carefully. It says you should have "z" litres of water in one of the jugs at the end, from where Manku has to drimk. The second last statement of the problem has it. "Now since he has no measuring device so he will do these operations only to make any of the 2 jug having exactly z litres of water." You should read the problem statements carefully rather than blaming the judge or saying the incorrectly framed question. |
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2015-08-16 15:28:45
:) |