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MINCOUNT - Move To Invert |
A triangle made of coins of height h is as follows:
- It has h coins at the base and h-1 coins one level above base and so on. (Coins are placed as shown in the figure below.)
- At the top-most level there will be only one coin.
Now given h, the task is to invert this triangle by moving the minimum number of coins.
For example when h=4 triangle is:
For h=4 at least 3 coins must be moved to invert it.
Input
In the first line N will be given and then N lines follow with each line having a integer which is the height of triangle in that test case. (0 ≤ h < 1010.)
Output
For each test case output in a separate line the minimum number of moves required to invert the triangle. Output fits in long long data type.
Example
Input: 1 3 Output: 2
Added by: | Abhilash I |
Date: | 2006-12-16 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ERL JS-RHINO |
Resource: | IIIT Hyderabad Local Programming Contest |
hide comments
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2021-10-12 08:01:49
Missing test cases now, isnt it? |
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2019-11-29 15:00:07
Hint:- " Read comments " ;) Last edit: 2020-01-02 21:08:32 |
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2019-07-29 18:12:45
~30000 testcases per file. |
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2017-07-22 11:01:42
only formula required....might be weak test cases... |
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2017-06-30 08:28:23
the moment u derive the formula....u get AC |
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2016-08-26 20:04:40
dont forget n=0, caused me 2 wa :( |
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2016-02-06 05:57:03 Utkarsh
observe the pattern |
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2016-01-28 13:34:35 Nallagatla Manikanta
AC in one go :) |
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2015-12-17 15:43:10
nice problem |
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2015-07-05 09:14:58 SangKuan
hard。 |