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MULPAL - Multiplicative Palindrome |
Given a sequence of N integers. Find two disjoint contiguous palindromic subsequences. Lets call them X and Y. Your task is to find X and Y such that product of their lengths is maximal possible.
Input
First line will contain one integer N (1 ≤ N ≤ 106).
Second line will contain N integers representing a sequence from the text of the task (0 ≤ Ai ≤ 2*109).
Output
First and only line of output should contain only one integer, the maximum possible product from the text of problem.
Example
Input: 2 1 1 Output: 1
Input: 4 1 1 2 2 Output: 4
Input: 6 10 11 12 12 11 10 Output: 4
Input: 6 0 1 0 1 0 1 Output: 9
Added by: | Zvonimir Medic |
Date: | 2010-11-28 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | own problem |
hide comments
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2012-02-11 13:33:16 MarioYC
disjoint contiguous palindromic subsequences = disjoint palindromic substrings? (looking each number as a character) Last edit: 2012-12-24 01:17:59 |
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2011-10-15 21:35:11 Buda IM (retired)
Yes, my O ( N ) got TLE, some IO optimization took care of it. Last edit: 2011-10-15 21:38:26 |
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2011-01-26 07:44:32 Prabakaran
@Shaka Shadows:In ur post length(11 12 12 11)*length(10),in Y part 10 is not a palindrome.then hw can u consider it? i think the sol is len(11)*len(11)=4 |
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2010-12-17 10:04:15 Kinan Sarmini
If anyone is getting WA a lot, then you either forget n = 1 case or long long |
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2010-12-16 19:39:28 Siarhei Kulik
Time limit is a little strict. Even O(N) solution may not fit in the time. |
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2010-12-12 18:13:40 .::Manish Kumar::.
What was your Time-complexity? |
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2010-12-12 02:43:17 Shaka Shadows
Yes :). Besides, X and Y don't need to be one exactly after the other. Read the text carefully. |
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2010-12-11 19:16:17 .::Manish Kumar::.
So, ultimately it has nothing to do with numbers, numbers can be considered as a single element. Last edit: 2010-12-11 19:17:22 |
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2010-12-11 18:57:22 Shaka Shadows
No, the answer is 4 because length(11 12 12 11) * length(10) = 4 * 1 = 4. The problem asks for finding 2 disjoint and palindromic contiguous sequences, X and Y, such that length(X) * length(Y) is maximum. |
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2010-12-11 18:53:09 .::Manish Kumar::.
Is the answer to 3rd sample 4 because: length(11)*length(11) = 2*2 = 4 ? |