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NACCI - Nacci Fear |
We all know about the classical Fibonacci series, Fibonacci series is F(n) = F(n-1) + F(n-2). For this question we call it a 2-Nacci series as a new element is calculated as the sum of the last 2 terms of the series. For Fibonacci we assume F(0)=0 and F(1)=1. We define as new series N-Nacci where F(n) is the sum of the last n terms and here we assume that F(0)=0, F(1)=1, F(2)=2 ... F(n-1) = (n-1). Your task is to calculate the last K digits of the Lth term of the N-Nacci series (no leading zeros needed).
Constraints
2<=N<=30
K<=8
L<=1000000000
Input
The first line of the input denotes the number of test cases t (at most 10). Each line denotes a test case consisting of N, K, L.
Output
For each test case print the last K digits of the Lth term of the N-Nacci series.
Example
Input: 4 2 1 5 3 6 12 4 1 10 4 2 10 Output: 5 778 6 16
Added by: | Saransh Bansal |
Date: | 2011-03-09 |
Time limit: | 0.105s-1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | Own problem |
hide comments
2021-07-25 04:30:47 Waseem Ahmed
Read how to generate the nth term of the regular Fibonacci Series using matrix operations before attempting to solve this problem. |
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2019-05-16 20:26:32 DK...
If the last digits of the answer is ...00004 and k>=2, you should print 4 (no leading zeros is needed) |
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2015-02-24 18:35:08 Soma
suppose if lth term is 123400005 and k is 3 should i print 005 or 5 ? (i am actually printing 5 but got WA). |
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2014-09-29 04:13:46 Nikhil Verma
it's written we have to print k digits of the lth term... 778 is the 13th term i guess... 0,1,2,3,6,11,20,,37,68,125,230,423,778... and 5 is the 5 the term 0,1,2,3,5... which 1 to print :/ Last edit: 2014-09-29 04:14:10 |
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2012-08-03 07:58:01 devu
Dont do typecasting errors ,costed me 3 wrong answers!! |
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2012-06-30 22:10:32 Himanshu Srivastava
can k=0?? dnt knw why i am getting wrong answer.... Last edit: 2012-06-30 22:23:28 |
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2011-03-15 09:15:18 Saransh Bansal
for the first test case we calculate the normal fibonacci series.. where F(0)=0 F(1)=1 F(2)=1 F(3)=2 F(4)=3 F(5)=5 so last 1 digit of F(5) is 5 for second case F(0)=0 F(1)=1 F(2)=2 F(3)=3 F(4)=6 F(5)=11 F(6)=20... F(12)=778 as the number has less than 6 digits print it as no leading zeros required |
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2011-03-14 18:18:30 cegprakash
explanation for the testcases plz.. |