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NAJPF - Pattern Find |
Your task is so simple given a string and a pattern. You find the pattern on the given string. If found print how many time found the pattern and their index. Otherwise print ‘Not Found’
Input:
The input line consists of a number T (1 ≤ T ≤ 50) test cases.
For each case given two string number A,B. the string and the pattern 1 ≤|A|, |B| ≤10^6
All character will be lower case Latin character. And | | is the length of string.
Output:
For each case print the number (found pattern from the given string) next line there position And Otherwise print 'Not Found' without quota.
There will a blank line between two cases.
Sample:
Input |
Output |
3 |
3 |
Hints:
Added by: | Najmuzzaman |
Date: | 2014-10-23 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 GOSU |
hide comments
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2020-05-09 13:49:20
using kmp O(n+m) 0.38 sec |
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2020-05-01 14:30:01
rabin karp AC one go :) |
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2020-04-14 21:11:43
can be done by brute force with a time complexity of O(n) Last edit: 2020-04-14 21:13:25 |
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2020-04-05 23:48:27
AC with Polynomial Hashing: 0.24s |
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2019-12-02 18:02:13
with Z algo in 0.19 secs |
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2019-11-14 18:27:48
Guys beware of giving the space between numbers.it cost me many WA -___- |
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2019-10-31 08:09:37
ac with kmp in .16 s |
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2019-10-15 03:02:07
If you are doing rabin-karp, and getting TLE, make sure you take care of the case when hash becomes -ve. Simply add mod to it. |
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2019-09-08 14:32:08
test case is rather weak, submiited a wrong solution and got accepted test case : aabaaabaaac aabaaac |
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2019-08-21 21:43:00
ac from first hit using z algorithm |