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NDS - Increasing numbers |
Subham and Dewang both are playing with numbers. Subham gives Dewang an array of numbers and asks him to tell the minimum possible last number of a increasing sequence of length L.
Note: Check the sample I/O for more clarity.
Input
Input consists of number of test cases T. Each test case contains size of array i.e N. Next line contains N space separated elements of array. Next line contains length of the increasing sequence i.e. L.
Constraignts
1 ≤ T ≤ 100
0 ≤ N ≤ 106
0 ≤ a[i] ≤ 106
Output
You have to print the minimum possible last number of a sequence and if their is no increasing sequence of length L, then print "-1" without the quotes.
Example
Input: 1 7 9 7 2 5 4 11 12 3 Output: 11
Explanation
In sample input, possible increasing sequences of length L = 3 are (9, 11, 12), (7, 11, 12), (2, 5, 11), (2, 4, 11), (2, 5, 12), (2, 4, 12), (2, 11, 12), (5, 11, 12), (4, 11, 12) and the minimum last number is 11 for the sequences (2, 5, 11) and (2, 4, 11). Hence, the answer is 11.
Added by: | Buttman |
Date: | 2016-07-06 |
Time limit: | 0.100s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 GOSU JS-MONKEY |
hide comments
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2020-07-15 07:18:58
easy one ,fenwick tree(just try LIS ends with a[i]) |
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2020-05-28 13:44:54
For those getting WA, just output -1 for any "L" greater than your LIS size. |
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2019-12-24 04:30:21
Can L be zero? |
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2019-11-27 20:05:13
Easy problem LIS with binary search happy coding |
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2019-08-11 22:49:34
O(n*log(n) * T) = O(10^6*20*100) = O(20*10^8) => 20 sec??? |
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2019-07-22 09:20:07
LIS nlogn |
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2019-01-10 12:29:14
@mahilewets can you please tell your logic behind this question. I am struggling on this problem from long time. i used segment trees but got an WA at testcase 7 |
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2018-06-21 10:49:33
just LIS in nlogn. |
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2018-01-04 07:30:05
easy BIT. |
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2017-09-06 11:59:01
Fenwick tree enough. |