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NFACTOR - N-Factorful |
A number is called n-factorful if it has exactly n distinct prime factors. Given positive integers a, b, and n, your task is to find the number of integers between a and b, inclusive, that are n-factorful. We consider 1 to be 0-factorful.
Input
Your input will consist of a single integer T followed by a newline and T test cases. Each test case consists of a single line containing integers a, b, and n as described above.
T > 10000
1 ≤ a ≤ b ≤ 106
0 ≤ n ≤ 10
Output
Output for each test case one line containing the number of n-factorful integers in [a, b].
Example
Input: 5 1 3 1 1 10 2 1 10 3 1 100 3 1 1000 0 Output: 2 2 0 8 1
Added by: | periclesmachado |
Date: | 2011-01-30 |
Time limit: | 1.879s-2.484s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | Facebook Hacker Cup 2011 Round 1C |
hide comments
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2017-01-24 15:17:58
NIce one simple at first look but indeed not :) |
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2017-01-19 19:31:16
Tonnes of optimizations finally got AC in 0.03........#1 in the c++14 and #4 in overall rankings:D Last edit: 2017-01-21 07:11:59 |
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2016-12-28 07:55:29
Modified sieve + Precomputation ... TLE :( ->->-> AC :) |
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2016-10-15 19:41:47
USed lower and upper bound stl and stored in Map.My 50th :) |
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2016-10-05 00:59:22
modified sieve + precomputation => AC in 0.18 sec |
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2016-07-17 11:57:19
nice implementation of sieve and memorization :) |
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2016-07-06 20:52:55 Deepak
finally AC : ) ....in .12. |
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2016-04-03 19:37:16
modified sieve ... may be nothing else... |
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2016-03-12 21:21:08
SUCH A NICE PROBLEM...GET AC AFTER 5-6 attempts |
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2016-03-05 16:47:59
AC in one go!!! |