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NPC2014A - I Ken Bit Yu |
On a hot day in Surabaya, Puguh is bored. He then declares himself as "the bestest player in teh wurld", challenging his friend named Joke to play a game. Here is the description of the game:
- There are N piles of coins and each pile contains Xi coins (i=1 to N).
- Each player alternately takes turn.
- On each turn, a player must take a number of coin from any pile. The number of coin taken must be a divisor of the current pile size and must be less than the current pile size. For example, if Puguh chooses a pile with 6 coins, then he may take 1, 2, or 3 coins from that pile.
- The first player that can't take any coin on his turn loses.
Puguh and Joke will play optimally. If Puguh is the first player to move, predict the winner of this game.
Input
Input starts with a number T, the number of test cases. For each test case, the first line contains a number N. The next line contains N numbers Xi, number of coins on the i-th pile.
Output
For each case, output a line. If Puguh won the game, output "Puguh is the bestest player in teh wurld" and if Joke won the game, output "Joke is the bestest player in teh wurld".
Sample Input
1
1
6
Sample Output
Puguh is the bestest player in teh wurld
Constraint
- 1 ≤ T ≤ 50
- 0 ≤ N ≤ 100000
- 0 ≤ Xi ≤ 1000000000
Input file is huge, use faster I/O (scanf for C)
Added by: | Andy |
Date: | 2014-10-21 |
Time limit: | 0.5s-0.800s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | NPC Schematics 2014 |
hide comments
2016-10-23 12:23:58
nim problems are the bestest in teh wurld,:P |
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2015-06-25 21:31:39
Great Problem mind the n=0 , x=0 Last edit: 2015-06-25 21:31:56 |
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2015-05-16 12:23:56 Pranjal Shankhdhar
RIP English :P |
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2014-10-31 11:00:35 Akhilesh Anandh
Awesome problem :) |
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2014-10-27 10:33:48 Aditya Pande
Nice problem Learnt a lot from this problem :) @surayans tiwari: 0 is a terminal i.e losing position |
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2014-10-24 00:16:39 surayans tiwari(http://bit.ly/1EPzcpv)
what for 0? |
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2014-10-24 00:16:39 Jacob Plachta
It's worth clarifying that the number of coins you take must be a divisor of the current pile size (as opposed to the original Xi value), and that there are of course no valid moves for an empty pile. Andy: updated the description, thanks! Last edit: 2014-10-22 09:33:29 |