ONEZERO - Ones and zeros

Certain positive integers have their decimal representation consisting only of ones and zeros, and having at least one digit one, e.g. 101. If a positive integer does not have such a property, one can try to multiply it by some positive integer to find out whether the product has this property.

Input

Number K of test cases (K is approximately 1000);
In each of the next K lines there is one integer n (1 ≤ n ≤ 20000)

Output

For each test case, your program should compute the smallest multiple of the number n consisting only of digits 1 and 0 (beginning with 1).

Example

Input:
3
17
11011
17

Output:
11101
11011
11101

Added by:Paweł Dobrzycki
Date:2005-05-26
Time limit:8s
Source limit:4096B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: NODEJS PERL6 VB.NET
Resource:II Polish Olympiad in Informatics, Ist Stage

hide comments
2018-07-22 14:15:05
If one is using C++ then for numbers like n=19999,19953, etc. the multiples will exceed the limit of int and eventually you will have to use string. You will have to create a separate function for longDivision. If one is using python then it is very easy problem for python users.
For C++ users the approach is like this:
1. Code to generate binary numbers -- this is simple bfs problem.
2. Perform long division.

Last edit: 2018-07-22 14:15:45
2018-06-03 19:19:57
Great problem!!
Weak test cases though :(
2018-03-14 18:29:44
thanks to tarun
2018-02-24 05:46:21
For optimizing bfs : https://www.geeksforgeeks.org/find-the-smallest-binary-digit-multiple-of-given-number/
2018-01-22 15:40:35
Nice problem, lot of things to take care of
2017-11-07 21:20:34
test cases are weak , there is no test case having n=1 boundary condition . Please improve the test case for this particular question .
2017-10-20 15:47:04
getting WA can someone help wrong answer code is https://ideone.com/SMd9dj
2017-10-17 17:11:10
did it using bfs ......but used modular arithmetic for checking remainder....it took me 5.44sec but AC in first go.Can anybody help me with my implementation....
2017-10-17 10:37:54
If you come here to practice BFS, look elsewhere. It's basically a bruteforce trial division over binary-looking numbers. People raving about smart-sounding acronyms here remind me of binmen calling themselves "environmental officers".
2017-09-20 13:28:01
Fcking awesome!!! Question worth giving time!
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