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PT07J - Query on a tree III |
You are given a node-labeled rooted tree with n nodes.
Define the query (x, k): Find the node whose label is k-th largest in the subtree of the node x. Assume no two nodes have the same labels.
Input
The first line contains one integer n (1 <= n <= 105). The next line contains n integers li (0 <= li <= 109) which denotes the label of the i-th node.
Each line of the following n - 1 lines contains two integers u, v. They denote there is an edge between node u and node v. Node 1 is the root of the tree.
The next line contains one integer m (1 <= m <= 104) which denotes the number of the queries. Each line of the next m contains two integers x, k. (k <= the total node number in the subtree of x)
Output
For each query (x, k), output the index of the node whose label is the k-th largest in the subtree of the node x.
Example
Input: 5 1 3 5 2 7 1 2 2 3 1 4 3 5 4 2 3 4 1 3 2 3 2 Output: 5 4 5 5
Added by: | Thanh-Vy Hua |
Date: | 2007-04-07 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ERL JS-RHINO NODEJS PERL6 VB.NET |
Resource: | Co-author Amber |
hide comments
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2024-10-23 18:37:22
Pretty Ohio. I submitted Mo + Ordered set. |
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2015-10-06 14:41:09
(n+m)logn 1s passed, with no stl. |
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2014-12-15 12:30:46 李子通
I used Mo's algorithm and made blocks based on values.O(m*(sqrt(n)+sqrt(m))). It was accepted.Because its constant is really small. 13170892 2014-12-15 12:26:34 Query on a tree III accepted edit run 0.38 12M C++ 4.3.2 |
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2014-07-15 17:55:27 Raghuram
nlogn +mlogn = tle, with the dirtiest IO optimizations and no stl Last edit: 2014-07-15 17:57:47 |
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2014-03-11 01:21:39 Hussain Kara Fallah
Actually Aced log^2 for query buuut no STL -_- |
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2014-01-11 12:43:11 adze
All test cases indicate k'th smallest. Please clarify. |
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2013-09-07 15:53:52 vit
nlogn - tle, i <3 this OJ |
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2013-04-26 23:47:45 Zhouxing Shi
kth largest or kth smallest? |
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2012-01-15 11:50:41 kipoujr
Just changed my c++ vectors with malloc, and passed the time limit. |
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2011-04-01 17:03:21 Govardhan Reddy M
cant understand the role of labels ?? |