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PT07Y - Is it a tree |
You are given an unweighted, undirected graph. Write a program to check if it's a tree topology.
Input
The first line of the input file contains two integers N and M --- number of nodes and number of edges in the graph (0 < N <= 10000, 0 <= M <= 20000). Next M lines contain M edges of that graph --- Each line contains a pair (u, v) means there is an edge between node u and node v (1 <= u, v <= N).
Output
Print YES if the given graph is a tree, otherwise print NO.
Example
Input: 3 2 1 2 2 3 Output: YES
Added by: | Thanh-Vy Hua |
Date: | 2007-03-28 |
Time limit: | 0.5s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ERL JS-RHINO |
Resource: | Co-author Amber |
hide comments
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2017-08-13 20:12:03
my code got accepted on codechef but was'nt accepted by spoj |
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2017-08-08 06:42:07
AC in one GO !! simple dfs |
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2017-07-22 08:11:38
I used DFS but getting NZEC error :| |
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2017-07-18 12:23:07
good use of DSU no need of DFS :P AC in first go |
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2017-07-13 14:05:38
you just need to know what is a tree topology. Thereafter it is a cakewalk. |
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2017-07-10 09:50:21
Connected and |e|=|v|-1 ! |
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2017-07-06 17:29:26
Nice Question.!! check for parent and unvisited nodes. |
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2017-06-24 01:21:57
Use Disjoint Set, Straightforward :D AC in One Go |
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2017-06-20 14:43:40
cases are too weak. |
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2017-06-12 11:59:38
if(m!=n-1 || n==1)cout<<"NO"; then run dfs....check cycle...if not YES else no AC!!...easy |