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PUCMM025 - Divisor Digits |
Given a number, output how many digits of that number the number is itself divisible by. Count all occurrences of such digits in the number, not just the first.
For example, 12345 is divisible by 1, 3, and 5, so, the answer in this case must be 3.
Input
Each test case is a number between 1 and 10240.
Output
for each test case, output how many of its digits divide the number.
Example
Input: 12345 661232 312 730000000 Output: 3 3 3 0
Added by: | Olson Ortiz |
Date: | 2011-12-08 |
Time limit: | 0.207s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | C CSHARP C++ 4.3.2 CPP JAVA |
Resource: | Used in 2da Olimpiada de Programacion PUCMM-ACM-ISC (fase 2) |
hide comments
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2013-09-23 07:13:41 rajul
extra test cases pls... |
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2013-08-30 19:15:55 flop_coder
use divisibility rules.....got ac :D |
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2013-08-07 20:09:50 @DubeY@
completed half century !!! easy one but do carefully!! |
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2013-07-31 17:26:14 P_Quantum
easy one..!! |
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2013-07-21 19:34:30 ***
nice one!!! |
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2013-07-04 12:25:56 Vijay Jain
after solving this try this one http://www.spoj.com/problems/NITT2/ |
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2013-05-30 02:43:12 Chandan Mittal
The divisibility by 7 costed me 5WA but finally got AC :) Last edit: 2013-05-31 03:16:21 |
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2013-03-26 17:51:36 Akb
easy one but do it carefully...!! |
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2013-03-12 18:05:35 Vipul Pandey
Nice one! |