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PUCMM210 - A Summatory |
f(n) is defined as: f(n) = 13+23+33+...+n3, so it is the sum of the cubes of all natural numbers up to n.
In this problem you are about to compute,
f(1) + f(2) + f(3) + ... + f(n)
Input
The first line is an integer T (1 ≤ T ≤ 100,000), denoting the number of test cases. Then, T test cases follow.
For each test case, there is an integer n (1 ≤ n ≤ 1,000,000) written in one line.
Output
For each test case output the result of the summatory function described above.
Since this number could be very large, output the answer modulo 1,000,000,003.
Example
Input:
3
2
10
3
Output:
10
7942
46
Added by: | Olson Ortiz |
Date: | 2012-05-24 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All |
Resource: | Used in 2nd dominican ACM-ICPC Warm Up 2012 Competition in PUCMM |
hide comments
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2013-10-25 00:47:50 omar alkattan
AC :) Be careful about modulo in subtracting |
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2013-09-23 20:38:35 BLANKRK
huhh.. finaly done!! |
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2013-08-02 05:55:54 Sanchit Manchanda
Getting SIGSEGV for this code. Any idea whats wrongs. <snip> Last edit: 2022-07-12 22:49:12 |
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2013-07-22 17:43:59 ***
ans for n=1000000? |
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2013-06-23 18:27:22 shiv prasad chabarval
mod caused 11 WA's... huh AC with a very bad timing 2.02. |
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2013-06-16 16:03:30 Gaurav Khewal
my century!!!! |
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2013-05-18 08:51:14 rafiki93
can you please give some big number test cases.have used mod literally everywhere but still getting wrong ans |
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2013-05-01 16:36:11 yaswanth
very simple!! similar to http://www.spoj.com/problems/SUMPOWK1/ |
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2013-04-30 02:46:40 Arika Saputro
i reduce from 11 branch to 2 branch and the time only reduced by 0.01 =( |
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2013-04-03 06:31:21 [Lakshman]
finally AC after several TLE,used precomputation to pass the time limit. |