QCJ4 - Minimum Diameter Circle

Given n points in a plane find the diameter of the smallest circle that encloses all the points. A point lying on the circle is also considered to be inside it.

Input

First line of input contains the n (<301) the number of points in the plane , followed by n lines of input. Each line gives the coordinates of one point on the plane. Each coordinate is an integer in the range [0, 1000]

Output

Output consists of a single real number, the diameter of the circle rounded to two decimal places.

Example

Input:
4
1 1
1 0
0 1
0 0

Output: 
1.41

Added by:abhijith reddy d
Date:2010-02-01
Time limit:0.208s-1s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: NODEJS OBJC PERL6 SQLITE VB.NET
Resource:CCC [Own Input]

hide comments
2013-11-22 19:42:41 M Sudeep Kumar
@abdou 00 687.53
2013-01-21 20:13:29 abdou_93
what is the answer for
5
886 383
915 777
335 793
492 386
421 649
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