STPAR - Street Parade

For sure, the love mobiles will roll again on this summer's street parade. Each year, the organisers decide on a fixed order for the decorated trucks. Experience taught them to keep free a side street to be able to bring the trucks into order.

The side street is so narrow that no two cars can pass each other. Thus, the love mobile that enters the side street last must necessarily leave the side street first. Because the trucks and the ravers move up closely, a truck cannot drive back and re-enter the side street or the approach street.

You are given the order in which the love mobiles arrive. Write a program that decides if the love mobiles can be brought into the order that the organisers want them to be.

Input

There are several test cases. The first line of each test case contains a single number n, the number of love mobiles. The second line contains the numbers 1 to n in an arbitrary order. All the numbers are separated by single spaces. These numbers indicate the order in which the trucks arrive in the approach street. No more than 1000 love mobiles participate in the street parade. Input ends with number 0.

Output

For each test case your program has to output a line containing a single word "yes" if the love mobiles can be re-ordered with the help of the side street, and a single word "no" in the opposite case.

Example

Sample input:
5
5 1 2 4 3 
0

Sample output:
yes

Illustration

The sample input reflects the following situation:

The five trucks can be re-ordered in the following way:


Added by:Patryk Pomykalski
Date:2004-07-01
Time limit:1s-2s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: NODEJS PERL6 VB.NET
Resource:Swiss Olympiad in Informatics 2004

hide comments
2015-06-25 17:49:04
AC in first Go ! Thanks @Liber (China)
2015-06-22 07:39:35 [Mayank Pratap]
If u have solved ONP this is just 5min problem.......Got 2 sigsegv for not using n==0 break condition ....
2015-06-21 14:39:05 mohit
only one logic.. find the deciding condition for 'no' in terms of the lane's stack.
2015-06-19 05:32:28 SangKuan
thanks Liber(China)
2015-06-18 21:09:53 king
AC in fist attempt :) :D thanx for the test cases by Liber(China) ... :)
2015-06-16 08:02:01 swap
Accepted !! :)
Thanks @Liber(China)
2015-06-13 19:07:48 hacker
nice question thanx to libra
AC in first attempt
2015-06-13 07:13:46
AC in first attempt. Thanks to @Liber(China) for the test cases. Hint: use while loop + stacks + critical reasoning
2015-06-10 21:17:40
Thank you @liber(China) for your test cases
2015-06-01 17:42:08 hanstan
Finally Acc :D
thanks to the testcases from @Liber (China)
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