SUBS - String it out

Let A and B be two strings made up of alphabets such that A = A[1-n], B = B[1-m]. We say B is a subsequence of A if there exists a sequence of indices i1 < i2 <..m of A such that A[ik] = B[k].

Given B[1-m], a string of characters from some alphabets, Bi is defined as string with the characters of B each repeating i times. For example, (abbacc)3 = aaabbbbbbaaacccccc. Also, B0 is the empty string.

Given strings X, Y made up of characters from 'a' - 'z' find the maximum value of M such that XM is a subsequence of Y.

Input

  • The first line of the input contains a positive integer t ≤ 20, denoting the number of test cases.
  • The following 2t lines contain the value of X and Y for the cases.
  • The description of the test cases follow one after the other.
    • Line 2k contains the value of X for case k; (1 ≤ k ≤ t)
    • Line 2k+1 contains the value of Y for case k; (1 ≤ k ≤ t).
    • The number of characters in X , Y will be ≤ 500010.

Output

The output must contain t lines, each line corresponding to a test case. The value on the kth line should be the value of M for the kth pair of X and Y.

Example

Input:
3
abc
aabbcc
abc
bbccc
abcdef
abc

Output:
2
0
0

Added by:Kashyap KBR
Date:2005-12-12
Time limit:4.823s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: NODEJS PERL6 VB.NET

hide comments
2021-07-23 11:48:50
How abc is subsequence of aaabbzbccc?
2021-03-08 21:33:55
AC in 1st go lol so easy!! :-)
2020-04-17 23:14:26
Can someone tell me in first test case string (X)^0 ,( X)^1 and (X)^2 is also sub sequence of string Y?
2020-03-12 15:44:02
AC in 1 go!
2020-01-08 12:31:25
I really don't know how to solve it using binary search... I used hash map to get AC
2019-05-21 20:59:08
Easier one..
Ac in one go Not using binary search
2018-05-04 09:31:40
Though you get AC without binary search also, really appreciate beauty of problem.
2017-09-09 08:25:16 Abhinav Gupta
Getting TLE even after applying binary search.
2017-08-24 20:51:56
AC in first attempt.. :D good question
2016-07-06 14:23:22
AC in 1st Go!!
Nice Problem!!
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