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ABCDEF - ABCDEF |
You are given a set S of integers between -30000 and 30000 (inclusive).
Find the total number of sextuples that satisfy:
Input
The first line contains integer N (1 ≤ N ≤ 100), the size of a set S.
Elements of S are given in the next N lines, one integer per line. Given numbers will be distinct.
Output
Output the total number of plausible sextuples.
Examples
Input: 1 1 Output: 1 |
Input: 2 2 3 Output: 4 |
Input: 2 -1 1 Output: 24 |
Input: 3 5 7 10 Output: 10 |
Added by: | Luka Kalinovcic |
Date: | 2009-07-13 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ERL JS-RHINO NODEJS PERL6 VB.NET |
Resource: | own problem |
hide comments
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2016-11-08 23:26:41
shvkppl: binary-search is just a way to solve it, and not the most efficient one, IMHO. |
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2016-11-04 17:43:34
is this actually a binary-search problem? |
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2016-10-20 15:51:50
can some one please explain me the question by solving a testcase manually....since i didnt understand the question |
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2016-09-28 18:47:35
Even though unordered_map uses O(n^3) and bounds uses O(n^3logn) ,, map tle's while upper and lower bound got ac |
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2016-09-10 13:41:09
My 15th :P . Tricky one case when D==0 |
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2016-09-07 10:10:50 Shivam
HashMap<Integer , Integer> times out. Any ideas why ? |
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2016-09-04 13:17:38 Mihir Saxena
Kept on getting a TLE repeatedly on using MAP structure, just replaced the map keyword by unordered_map all over the program, rest of the code was the same and got accepted :) |
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2016-08-19 17:33:01
accepted in 2nd go --> 2 vectors for lhs nd rhs --> 1 sort function for rhs vector --> lower and upper for lhs in rhs --> cout<<ub-v2.begin())-(lb-v2.begin(); |
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2016-08-06 21:59:05
how is it happening can't understand plz help |
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2016-08-04 07:12:21
Map will make you get TLE. Use lower_bound and upper_bound guys. O(n^3.logn). GL |