Submit | All submissions | Best solutions | Back to list |
ABCDEF - ABCDEF |
You are given a set S of integers between -30000 and 30000 (inclusive).
Find the total number of sextuples that satisfy:
Input
The first line contains integer N (1 ≤ N ≤ 100), the size of a set S.
Elements of S are given in the next N lines, one integer per line. Given numbers will be distinct.
Output
Output the total number of plausible sextuples.
Examples
Input: 1 1 Output: 1 |
Input: 2 2 3 Output: 4 |
Input: 2 -1 1 Output: 24 |
Input: 3 5 7 10 Output: 10 |
Added by: | Luka Kalinovcic |
Date: | 2009-07-13 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ERL JS-RHINO NODEJS PERL6 VB.NET |
Resource: | own problem |
hide comments
|
||||||||||||||
2018-05-25 10:10:45
Can anyone help me to solve it faster . I got ac in 1 go but time was 2.38 sec . How even peoples have solved it in less than 0.1 sec . please help @aexpo Last edit: 2018-05-25 10:11:22 |
||||||||||||||
2018-05-15 19:44:11
This question completely baffles me. First of all unordered_map works and map doesn't. why are you tagged #binary-search then? Next unordered_multiset doesn't work but unordered_map does??!! why? |
||||||||||||||
2018-05-10 17:39:00
Be careful about d != 0. |
||||||||||||||
2018-03-31 12:58:05
AC in 2nd go!! Used unordered_map and lower_bound,upper_bound! |
||||||||||||||
2018-02-18 08:16:08
use simple approach ......and dont think complex. Last edit: 2018-02-18 08:17:42 |
||||||||||||||
2018-02-04 11:48:40
Rearrange the given expression as [ (a*b)+c = d*(e+f) ]. Now, store possible values for LHS in a vector(say v1) and possible values for RHS in another vector(say v2). Now, sort v2 and iterate over elements of v1 and check how many elements in v2 are same as current element in v1. Now, add those many elements to the count. This can be easily accomplished by using equal_range in C++ which returns the iterators to both lower_bound and upper_bound(simply subtracting both the iterators will give you the number of elements in v2 which are same as the current element in v1) |
||||||||||||||
2018-01-19 20:58:02
I am getting TLE although my java solution solves all test cases in ide. Can anyone suggest something? is it allowed to post code in the comments section |
||||||||||||||
2017-12-23 17:41:28
my complexity is O(n*(lgn+n)). it is coming tle. any suggestions |
||||||||||||||
2017-12-19 20:35:14
Similar to SUMFOUR!!! |
||||||||||||||
2017-12-06 10:34:50
can any body explain problem with example |