Submit | All submissions | Best solutions | Back to list |
ABCPATH - ABC Path |
You will be given a 2-dimensional grid of letters. Find the length of the longest path of consecutive letters, starting at 'A'. Paths can step from one letter in the grid to any adjacent letter (horizontally, vertically, or diagonally).
For example, in the following grid, there are several paths from 'A' to 'D', but none from 'A' to 'E':
One such path is:
Input
Each test case will start with a line contains two integers H, W the height and width of the grid respectively 1 <= H, W <= 50. Then H lines follow each of W uppercase letters only. Input terminates with H = 0 and W = 0.
Output
For each test case print “Case C: X” without quotes where C is the case number starting with 1 and X is the solution.
Example
Sample Input: 4 3 ABE CFG BDH ABC 0 0 Sample Output: Case 1: 4
Added by: | Ali Arous |
Date: | 2011-11-05 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | FCIS Local Contest 2012 |
hide comments
|
||||||||||||||
2018-07-05 15:23:11
Simple DFS !! Just make once used characters unusable for further times as they can never help to reach farther than they did last time ;) |
||||||||||||||
2018-05-25 16:51:05
Good one Last edit: 2018-05-26 06:23:18 |
||||||||||||||
2018-02-04 07:39:51
use multi-source bfs |
||||||||||||||
2018-01-17 18:00:13
AC in 1 go. :) Simple recursion and memo.. |
||||||||||||||
2017-12-23 08:44:59
nice practice question:) |
||||||||||||||
2017-08-28 07:57:04
Try this. Input: 1 1 B 1 2 AA 1 1 A 1 1 B 5 3 ABF CFG OQP DCB PQA 0 0 Output: Case 1: 0 Case 2: 1 Case 3: 1 Case 4: 0 Case 5: 4 Last edit: 2017-08-28 07:59:32 |
||||||||||||||
2017-08-13 09:27:12
used recursion :) |
||||||||||||||
2017-07-30 19:56:06
Can not figure out an iterative solution though.. |
||||||||||||||
2017-07-22 19:22:59
simple DFS...dont forget the case when no 'A' is present!! |
||||||||||||||
2017-06-18 11:22:10
just dfs with memo..otherwise tle. ;-) |